有没有办法在PHP中找到月份差异？我有从2003-10-17到2004-03-24的输入。我需要找到这两天内有多少个月。比如说6个月，我只需要几个月的输出。感谢您指导我一天的差异。
我通过MySQL找到解决方案，但我需要在PHP中使用它。有人帮助我，提前谢谢。
答案 0 :(得分：63)
没有重新发明轮子的最简单方法。这将为您提供完整月份差异。即以下两个日期几乎相隔76个月，但结果是75个月。
date_default_timezone_set('Asia/Tokyo'); // you are required to set a timezone
$date1 = new DateTime('2009-08-12');
$date2 = new DateTime('2003-04-14');
$diff = $date1->diff($date2);
echo (($diff->format('%y') * 12) + $diff->format('%m')) . " full months difference";
答案 1 :(得分：19)
在测试了大量的解决方案后，将所有解决方案全部用于单元测试，这就是我提出来的：
/**
* Calculate the difference in months between two dates (v1 / 18.11.2013)
*
* @param \DateTime $date1
* @param \DateTime $date2
* @return int
*/
public static function diffInMonths(\DateTime $date1, \DateTime $date2)
{
$diff = $date1->diff($date2);
$months = $diff->y * 12 + $diff->m + $diff->d / 30;
return (int) round($months);
}
例如，它将返回（来自单元测试的测试用例）：
注意：由于它与日期的四舍五入，甚至半个月都会四舍五入，如果你在某些情况下使用它可能会导致问题。所以不要在这种情况下使用它，它会引起你的问题。
例如：
答案 2 :(得分：7)
我只是想添加这个，如果有人正在寻找一个简单的解决方案，计算每个触及的月份，而不是完整的几个月，几个月或类似的东西。
// Build example data
$timeStart = strtotime("2003-10-17");
$timeEnd = strtotime("2004-03-24");
// Adding current month + all months in each passed year
$numMonths = 1 + (date("Y",$timeEnd)-date("Y",$timeStart))*12;
// Add/subtract month difference
$numMonths += date("m",$timeEnd)-date("m",$timeStart);
echo $numMonths;
答案 3 :(得分：6)
function monthsBetween($startDate, $endDate) {
$retval = "";
// Assume YYYY-mm-dd - as is common MYSQL format
$splitStart = explode('-', $startDate);
$splitEnd = explode('-', $endDate);
if (is_array($splitStart) && is_array($splitEnd)) {
$difYears = $splitEnd[0] - $splitStart[0];
$difMonths = $splitEnd[1] - $splitStart[1];
$difDays = $splitEnd[2] - $splitStart[2];
$retval = ($difDays > 0) ? $difMonths : $difMonths - 1;
$retval += $difYears * 12;
}
return $retval;
}
注意：与其他几个解决方案不同，这不依赖于PHP 5.3中添加的日期函数，因为许多共享主机还没有。
答案 4 :(得分：2)
http://www.php.net/manual/en/datetime.diff.php
这将返回一个具有格式方法的DateInterval对象。
答案 5 :(得分：0)
<?php
# end date is 2008 Oct. 11 00:00:00
$_endDate = mktime(0,0,0,11,10,2008);
# begin date is 2007 May 31 13:26:26
$_beginDate = mktime(13,26,26,05,31,2007);
$timestamp_diff= $_endDate-$_beginDate +1 ;
# how many days between those two date
$days_diff = $timestamp_diff/2635200;
?>
答案 6 :(得分：0)
function monthsDif($start, $end)
{
// Assume YYYY-mm-dd - as is common MYSQL format
$splitStart = explode('-', $start);
$splitEnd = explode('-', $end);
if (is_array($splitStart) && is_array($splitEnd)) {
$startYear = $splitStart[0];
$startMonth = $splitStart[1];
$endYear = $splitEnd[0];
$endMonth = $splitEnd[1];
$difYears = $endYear - $startYear;
$difMonth = $endMonth - $startMonth;
if (0 == $difYears && 0 == $difMonth) { // month and year are same
return 0;
}
else if (0 == $difYears && $difMonth > 0) { // same year, dif months
return $difMonth;
}
else if (1 == $difYears) {
$startToEnd = 13 - $startMonth; // months remaining in start year(13 to include final month
return ($startToEnd + $endMonth); // above + end month date
}
else if ($difYears > 1) {
$startToEnd = 13 - $startMonth; // months remaining in start year
$yearsRemaing = $difYears - 2; // minus the years of the start and the end year
$remainingMonths = 12 * $yearsRemaing; // tally up remaining months
$totalMonths = $startToEnd + $remainingMonths + $endMonth; // Monthsleft + full years in between + months of last year
return $totalMonths;
}
}
else {
return false;
}
}
答案 7 :(得分：0)
// get year and month difference
$a1 = '20170401';
$a2 = '20160101'
$yearDiff = (substr($a1, 0, 4) - substr($a2, 0, 4));
$monthDiff = (substr($a1, 4, 2) - substr($a2, 4, 2));
$fullMonthDiff = ($yearDiff * 12) + $monthDiff;
// fullMonthDiff = 16
答案 8 :(得分：0)
这是@deceze答案的增强版本：
/**
* @param string $startDate
* Current date is considered if empty string is passed
* @param string $endDate
* Current date is considered if empty string is passed
* @param bool $unsigned
* If $unsigned is true, difference is always positive, otherwise the difference might be negative
* @return int
*/
public static function diffInFullMonths($startDate, $endDate, $unsigned = false)
{
$diff = (new DateTime($startDate))->diff(new DateTime($endDate));
$reverse = $unsigned === true ? '' : '%r';
return ((int) $diff->format("{$reverse}%y") * 12) + ((int) $diff->format("{$reverse}%m"));
}
答案 9 :(得分：0)
最好的方法。
leadsheet.id结果：
function getIntervals(DateTime $from, DateTime $to)
{
$intervals = [];
$startDate = $from->modify('first day of this month');
$endDate = $to->modify('last day of this month');
while($startDate < $endDate){
$firstDay = $startDate->format('Y-m-d H:i:s');
$startDate->modify('last day of this month')->modify('+1 day');
$intervals[] = [
'firstDay' => $firstDay,
'lastDay' => $startDate->modify('-1 second')->format('Y-m-d H:i:s'),
];
$startDate->modify('+1 second');
}
return $intervals;
}
$dateTimeFirst = new \DateTime('2013-01-01');
$dateTimeSecond = new \DateTime('2013-03-31');
$interval = getIntervals($dateTimeFirst, $dateTimeSecond);
print_r($interval);
答案 10 :(得分：0)
在我的情况下，我需要计算整月和剩余的剩余时间，以构建折线图标签。
/**
* Calculate the difference in months between two dates
*
* @param \DateTime $from
* @param \DateTime $to
* @return int
*/
public static function diffInMonths(\DateTime $from, \DateTime $to)
{
// Count months from year and month diff
$diff = $to->diff($from)->format('%y') * 12 + $to->diff($from)->format('%m');
// If there is some day leftover, count it as the full month
if ($to->diff($from)->format('%d') > 0) $diff++;
// The month count isn't still right in some cases. This covers it.
if ($from->format('d') >= $to->format('d')) $diff++;
}
答案 11 :(得分：0)
$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2013-1-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%a day %m month %y year');
答案 12 :(得分：-5)
这是一个快速的：
$date1 = mktime(0,0,0,10,0,2003); // m d y, use 0 for day
$date2 = mktime(0,0,0,3,0,2004); // m d y, use 0 for day
echo round(($date2-$date1) / 60 / 60 / 24 / 30);