Question

现在我正在使用php和mySql构建自定义查询。说我有一个字符串你好，这是我。对于这个

select distinct(user_primary.id) as id 
from user_primary, 
user_sec, 
user_location, 
user_ind_cat 
where 
( 
 user_primary.status != 3 
 and 
 (
  user_primary.id = user_sec.job_id
 ) 
 and 
 (
  user_primary.id = user_ind_cat.job_id
 )
) 
and 
( 
 (
  user_primary.name like "%Hello%"
 ) 
 or 
 (
  user_primary.name like "%this%"
 ) 
 or 
 (
  user_primary.name like "%is%"
 ) 
 or 
 (
  user_primary.name like "%me%"
 ) 
 and 
 (
  user_primary.name like "%Hello this is me%"
 )
) 
and 
(
 user_primary.login <= 1415426357
) 
limit 0, 150

到目前为止它工作正常，直到最近我才发现了一个问题。每当我运行这种查询时，它生成的结果包含全名的用户，如搜索令牌和从搜索令牌生成的其他匹配令牌。但是与提供的标记“Hello this is me”完美匹配的实际行并未显示在顶部。

如果我运行当前查询，请让我解释一下结果

“你好，你好吗”
“这是尼克松”
“你好，这是我”
“哦，你好”
“我是我”
“你好，你好”

我想在顶部显示实际结果，因此结果将如下所示，

“你好，这是我”
“你好，你好吗”
“这是尼克松”
“哦，你好”
“我是我”
“你好，你好”

有人可以告诉我这里有什么问题吗？或者我应该删除或添加查询？

提前致谢，

尼克松

Answer 1

这听起来像是一份完整的文字索引！

 ALTER TABLE `user_primary` ADD FULLTEXT INDEX (`name`);

现在，MySQL已经创建了一个比你的OR链更模糊的文本搜索索引。因此，您的部分查询将如下所示：

 SELECT name, MATCH(name) AGAINST ('Hello this is me') as confidence 
     FROM user_primary
     WHERE MATCH(name) AGAINST ('Hello this is me')
     ORDER BY confidence DESC

匹配越好，confidence越高，所以＆＃34;你好，这就是我＆＃34;应该是最重要的。

这可能是您的查询，清理和未经测试：

select distinct(user_primary.id) as id , MATCH(name) AGAINST ('Hello this is me') as confidence
from user_primary, user_sec, user_location, user_ind_cat 
WHERE 
 user_primary.status != 3 
 and user_primary.id = user_sec.job_id 
 and user_primary.id = user_ind_cat.job_id
 and MATCH(name) AGAINST ('Hello this is me')
 and  user_primary.login <= 1415426357
ORDER BY confidence DESC
limit 0, 150

Answer 2

添加匹配分数并按其排序：

select distinct(user_primary.id) as id,

CASE user_primary.name 
  WHEN user_primary.name like "%Hello this is me%" THEN 100
  WHEN user_primary.name like "%Hello%" THEN 50
  WHEN user_primary.name like "%this%" THEN 40
  WHEN user_primary.name like "%is%" THEN 30
  WHEN user_primary.name like "%me%" THEN 10
  ELSE 0
END as sortScore


from user_primary, 
user_sec, 
-- user_location, 
user_ind_cat 
where 
user_primary.status != 3 
and user_primary.id = user_sec.job_id
and user_primary.id = user_ind_cat.job_id 
and 
( 
 user_primary.name like "%Hello this is me%"
  or user_primary.name like "%Hello%"
  or user_primary.name like "%this%"
  or user_primary.name like "%is%"
  or user_primary.name like "%me%"
)
and user_primary.login <= 1415426357
order by sortScore
limit 0, 150

通过搜索令牌问题的MYSQL自定义查询顺序

2 个答案: