Question

我正在寻找自己的调试Activity，然后在我的其他类中使用最少量的代码从各种其他类（不仅仅是像我在这里看到的其他问题的单个类）中更新它。所以前：

// activity class
public class DebugActivity extends Activity {
public TextView txtView;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
        TextView txtView = (TextView)findViewById(R.id.text);
}

public someMethod(String text) {
  //Update text view code here.

}

// A class updating the text view
public class Some other class {

    someOtherMethod {

        DebugActivity.someMethod(updatedTextViewSTring);
    }

}

Answer 1

我能想到的最简单的方法是将数据（文本）发送到DebugActivity。您需要在与<{1}}一起使用的每个 activity中使用此代码：

DebugActivity

并接受Intent i = new Intent(this, DebugActivity.class); i.putExtra("text", "some text"); startActivity(i); onCreate中的数据（文字）：

DebugActivity

注意：Theres 否用于实时更改Bundle b = getIntent().getExtras(); if(b!=null) String text = b.getString("text");中的textview，因为一次只显示一个Activity。

Answer 2

优雅的方法是使用EventBus lib https://github.com/greenrobot/EventBus

您需要在DebugActivity

中编写如下代码

EventBus.getDefault().register(this);
public void onEventMainThread(TextEvent textEvent)
{
    txtView.setText(textEvent.getText());
}

之后，您可以从App中的任何位置发送textevent，如下所示

eventBus.post(new TextEvent("my Message"));

或

Pure Android方式是使用Broadcast / Handler

Answer 3

以下是如何使用广播监视名为＆＃34; custom-event-name＆＃34;。

的事件的通知的活动

@Override
public void onCreate(Bundle savedInstanceState)
{
  // Register to receive messages.
  // We are registering an observer (mMessageReceiver) to receive Intents
  // with actions named "custom-event-name".
  LocalBroadcastManager.getInstance(this).registerReceiver(mMessageReceiver,new IntentFilter("custom-event-name"));
}

// Our handler for received Intents. This will be called whenever an Intent
// with an action named "custom-event-name" is broadcasted.
private BroadcastReceiver mMessageReceiver = new BroadcastReceiver() 
{
  @Override
  public void onReceive(Context context, Intent intent)
  {
    // Get extra data included in the Intent
    String message = intent.getStringExtra("message");
    Log.d("receiver", "Got message: " + message);
  }
};

以下是您将如何从app中发送消息

// Send an Intent with an action named "custom-event-name". The Intent sent should 
// be received by the ReceiverActivity.
private void sendMessage() 
{
  Log.d("sender", "Broadcasting message");
  Intent intent = new Intent("custom-event-name");
  // You can also include some extra data.
  intent.putExtra("message", "This is my message!");
  LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}

经常从多个类修改TextView

3 个答案: