Question

嗨，这是我第一次来到这里，因为我是第一次学习编码，所以我很难挣扎。我假设当我尝试将参数传递给参数时，它会混淆，或者我可能会错过一些非常简单的东西。我在哪里遗失或失败？我只是不工作......

  function adultCheck(age,name) {
  if (age <= 17) {
    alert("Sorry " + name ", you are not allowed to see this, you are too young.");
  } else {
    alert("Welcome " + name ", you are " + age "  visit our lounge!");
  }

}

adultCheck(15,Tami);

Answer 1

您需要在函数中的+和name个连词周围添加age个符号，并且应该在字符串中添加引号。像，

＆＃13;

function adultCheck(age, name) {
  if (age <= 17) {
    alert("Sorry " + name + ", you are not allowed to " 
          + "see this, you are too young.");
  } else {
    alert("Welcome " + name + ", you are " + age 
          + " visit our lounge!");
  }
}
adultCheck(15, 'Tami');

＆＃13;

Answer 2

你的第二个参数应该是一个字符串，所以它需要在引号中：

adultCheck(15, "Tami");

此外，您在变量周围遗漏了几个+符号：

function adultCheck(age, name) {
  if (age <= 17) {
    alert("Sorry " + name + ", you are not allowed to see this, you are too young.");
  } else {
    alert("Welcome " + name + ", you are " + age + " visit our lounge!");
  }
}

Answer 3

你也忘了在变量之后添加额外的+：＆＃34;＆＃34; +名称+＆＃34;＆＃34;

javascript中的基本功能无法正常工作

3 个答案: