Question

好的我使用以下代码为我的附件生成标题。问题是如果我在一个页面中有多个图像，则第一个图像的标题显示所有图像。就像我有＆＃34; Text One＆＃34;作为我的图像的标题之一，所有的图像显示了这个＆＃34; Text One＆＃34;字幕。我该如何解决这个问题？

 <?php 
$args = array( 'post_type' => 'attachment', 
                    'orderby' => 'menu_order', 
                    'order' => 'ASC', 
                    'post_mime_type' => 'image' ,
                    'post_status' => null, 
                    'numberposts' => 50, 
                    'post_parent' => $post->ID );

        $attachments = get_posts($args);
        if ($attachments) {
            foreach ( $attachments as $attachment ) {
                $caption = $attachment->post_excerpt;
                } 
             }
    ?>
    <p class="project-caption"><?php echo $caption ?></p>

目前有一个滑块，显示图像。＆安培;滑块代码是：

<?php
                if($repeater):
                    foreach($repeater as $r):
            ?>
                <li class="<?php echo $r["fit_to_screen"] ? "img_fit" : ""; ?>">
                    <?php
                    if($r["acf_fc_layout"] == "image"):
                    $html = "<img data-fit='".$r["fit_to_screen"]."' src='".$r["image"]["url"]."' alt='".$r["image"]["alt"]."'/>";
                    echo apply_filters( 'post_thumbnail_html', $html, $post->ID , $r["image"]["id"], "large" , array("alt"=>$r["image"]["alt"]) );
                    else:
                        echo getVideoEmbed($r["video_url"]);
                    endif;
                    ?>
                </li>
            <?php
                    endforeach;
                endif;
            ?>

Answer 1

你得到相同的标题，因为你在foreach之后显示标题，你应该在foreach中这样做：

<?php 
$args = array( 'post_type' => 'attachment', 
                'orderby' => 'menu_order', 
                'order' => 'ASC', 
                'post_mime_type' => 'image' ,
                'post_status' => null, 
                'numberposts' => 50, 
                'post_parent' => $post->ID );

    $attachments = get_posts($args);
    if ($attachments) {
        foreach ( $attachments as $attachment ) {
            $caption = $attachment->post_excerpt;
            echo '<p class="project-caption">' . $caption . '</p>';
            } 
         }
?>

Answer 2

你覆盖循环中的$caption，所以最后你会得到最后一个标题。

您可以在循环内打印$caption然后获得所有字幕。

foreach ( $attachments as $attachment ) {
    $caption = $attachment->post_excerpt;
    echo '<p class="project-caption">'.$caption.'</p>';
}

只有第一个标题显示在Wordpress中的附件

2 个答案: