Question

// This code lets the computer select the first random number from your array
int rn1 = boarduser[new Random().nextInt(boarduser.length)];
System.out.println("Computer's Value: " + rn1);

// This code lets the computer select the second random number from your array
int rn2 = boarduser[new Random().nextInt(boarduser.length)];
System.out.println("Computer's Value: "+ rn2);

boolean tokenduplicate1; // check if the computer took the same value twice

for (int j = 0; j < i; ++j) {
    if (rn2 == rn1) {
    tokenduplicate1 = true;}
    while (tokenduplicate1);

    // This code lets the computer select the third random number from your array
    int rn3 = boarduser[new Random().nextInt(boarduser.length)];
    System.out.println("Computer's Value: "+ rn3);

    boolean tokenduplicate2; // check if the computer took the same value twice

    for (int k = 0; k < i; ++k) {
        if (rn3 == rn1 || rn3 == rn2) {
        tokenduplicate1 = true;}
        while (tokenduplicate1);

我想首先说我对Java知之甚少，所以这里是

代码仍然不完整，但我要做的是检查boarduser中选择的随机变量是否与之前的值相同。如果是，我希望它在我的boarduser数组中选择另一个变量，直到它与前一个变量不同。

Answer 1

保持（重新）选择第二个值，直到它与第一个值不一致。

int rn1 = boarduser[new Random().nextInt(boarduser.length)];
System.out.println("Computer's Value: " + rn1);
int rn2 = boarduser[new Random().nextInt(boarduser.length)];
while(rn2 == rn1)
{
    rn2 = boarduser[new Random().nextInt(boarduser.length)];
}
System.out.println("Computer's Value: " + rn2);

Answer 2

您可以使用Set然后检查其长度。

int somevalue = 3; // if you want 3 values

Set<Integer> numbers = new LinkedHashSet<Integer>();
while(numbers.size() != somevalue) {
    numbers.add(new Random().nextInt(boarduser.length));
}

System.out.println(numbers);

打印例如：[11,1,5]

试图检查Java中的重复项

2 个答案: