Question

您好，

我有一个假模型（没有任何与之关联的表的实体），用于验证联系表单。我想从另一张桌子上取一封电子邮件。我创建了一个DataTranformer，并将其与我的模型的电子邮件字段绑定。

现在，当我尝试提交表单时，它给了我这个错误：

An exception occurred while executing 'SELECT t0.firstName AS firstName1, t0.lastName AS lastName2, t0.email AS email3,  FROM Contact t0 WHERE t0.email = ? LIMIT 1' with params [{}]:\n\nObject of class App\\ApiBundle\\Model\\EmailCo could not be converted to string"

如何解决这个问题。

这是我的模型类：

namespace App\ApiBundle\Model;

use Symfony\Component\Validator\Constraints as Assert;
use Symfony\Component\Validator\ExecutionContext;
use Doctrine\ORM\Mapping as ORM;

class EmailCo
{
    /**
     * @var string Email Id
     * @Assert\NotBlank()
     * @Assert\Email()
     */
    protected $email;

    /**
     * @var string Mail Subject
     * @Assert\NotBlank()
     * @Assert\Length(
     *      min = 3,
     *      max = 200,
     *      minMessage = "Subject must be at least {{ limit }} characters long",
     *      maxMessage = "Subject cannot be longer than {{ limit }} characters long"
     * )
     */
    protected $subject;

    /**
     * @var string The note message
     * @Assert\NotBlank()
     * @Assert\Length(
     *      min = 3,
     *      max = 200,
     *      minMessage = "Subject must be at least {{ limit }} characters long",
     *      maxMessage = "Subject cannot be longer than {{ limit }} characters long"
     * )
     */
    protected $message;

    /**
     * @var bool Send a copy to user or not
     * @Assert\NotBlank()
     */
    protected $sendCopyToMe;


    public function setEmail($email)
    {
        $this->email = $email;
    }

    public function getEmail()
    {
        return $this->email;
    }

    public function setSubject($subject)
    {
        $this->subject = $subject;
    }

    public function getSubject()
    {
        return $this->subject;
    }

    public function setMessage($message)
    {
        $this->message = $message;
    }

    public function getMessage()
    {
        return $this->message;
    }

    public function setSendCopyToMe($sendCopyToMe)
    {
        $this->sendCopyToMe = $sendCopyToMe;
    }

    public function getSendCopyToMe()
    {
        return $this->sendCopyToMe;
    }

}

Answer 1

错误消息显示对象无法转换为字符串。这通常通过函数__toString完成，您可以将其添加到EmailCo类：

public function __toString()
{
    return '...';
}

了解更多信息have a look here

Model和DataTransformer在Symfony2中不起作用

1 个答案: