Question

a.py：

def factory_a(name):
    return "A"

def run():
    a = factory_a("A")
    from b import factory_b 
    friend_of_a = factory_b("B")
    print(a)
    print(friend_of_a)

b.py：

def factory_b(name):
    return "B"

def run():
    b = factory_b("B")
    from a import factory_a 
    friend_of_b = factory_a("A")
    print(b)
    print(friend_of_b)

如果导入已放置在每个模块的开头而不是run()，那么由于循环导入，这将无法工作。因此，我想知道我是否正确地解决了这个问题，就像我在下面所做的那样。你会怎么做呢？

Answer 1

代码有效......现在，我不喜欢它。这种相互依赖使得代码难以理解和扩展。这样的事情看起来好多了：

a.py

def factory_a(name):
    return "A"

b.py

def factory_b(name):
    return "B"

controller.py

from a import factory_a     
from b import factory_b     

def run_a():
    a = factory_a("A")        
    friend_of_a = factory_b("B")
    print(a)
    print(friend_of_a)

def run_b():
    b = factory_b("B")
    friend_of_b = factory_a("A")
    print(a)
    print(friend_of_b)

打破循环依赖

1 个答案: