在我的WPF - C#应用程序中,我有一个耗时的功能,我用BackgroundWorker执行。此功能的作用是将文件中的给定数据添加到数据库中。偶尔,我需要一些用户反馈,例如数据已经存储在商店中,我想询问用户,他是想合并数据还是创建新对象或完全跳过数据。就像对话框窗口显示的那样,如果我尝试将文件复制到某个位置,那里已存在同名文件。
问题是,我无法从非GUI线程调用GUI窗口。我怎么能实现这种行为?
提前致谢,
弗兰克
答案 0 :(得分:1)
您可以使用EventWaitHandle ou AutoResetEvent,然后每当您想要提示用户时,您都可以使用信号UI,然后等待响应。有关该文件的信息可以存储在变量中。
答案 1 :(得分:0)
如果可能......我的建议是将长期运行的任务构建为原子操作。然后,您可以创建一个可供后台线程和UI线程访问的项目队列。
public class WorkItem<T>
{
public T Data { get; set; }
public Func<bool> Validate { get; set; }
public Func<T, bool> Action { get; set; }
}
你可以使用类这样的东西。它使用一个队列来管理工作项的执行,并使用一个可观察的集合来表示UI:
public class TaskRunner<T>
{
private readonly Queue<WorkItem<T>> _queue;
public ObservableCollection<WorkItem<T>> NeedsAttention { get; private set; }
public bool WorkRemaining
{
get { return NeedsAttention.Count > 0 && _queue.Count > 0; }
}
public TaskRunner(IEnumerable<WorkItem<T>> items)
{
_queue = new Queue<WorkItem<T>>(items);
NeedsAttention = new ObservableCollection<WorkItem<T>>();
}
public event EventHandler WorkCompleted;
public void LongRunningTask()
{
while (WorkRemaining)
{
if (_queue.Any())
{
var workItem = _queue.Dequeue();
if (workItem.Validate())
{
workItem.Action(workItem.Data);
}
else
{
NeedsAttention.Add(workItem);
}
}
else
{
Thread.Sleep(500); // check if the queue has items every 500ms
}
}
var completedEvent = WorkCompleted;
if (completedEvent != null)
{
completedEvent(this, EventArgs.Empty);
}
}
public void Queue(WorkItem<T> item)
{
// TODO remove the item from the NeedsAttention collection
_queue.Enqueue(item);
}
}
您的UI代码隐藏可能类似于
public class TaskRunnerPage : Page
{
private TaskRunner<XElement> _taskrunner;
public void DoWork()
{
var work = Enumerable.Empty<WorkItem<XElement>>(); // TODO create your workItems
_taskrunner = new TaskRunner<XElement>(work);
_taskrunner.NeedsAttention.CollectionChanged += OnItemNeedsAttention;
Task.Run(() => _taskrunner.LongRunningTask()); // run this on a non-UI thread
}
private void OnItemNeedsAttention(object sender, NotifyCollectionChangedEventArgs e)
{
// e.NewItems contains items that need attention.
foreach (var item in e.NewItems)
{
var workItem = (WorkItem<XElement>) item;
// do something with workItem
PromptUser();
}
}
/// <summary>
/// TODO Use this callback from your UI
/// </summary>
private void OnUserAction()
{
// TODO create a new workItem with your changed parameters
var workItem = new WorkItem<XElement>();
_taskrunner.Queue(workItem);
}
}
此代码未经测试!但基本原则应该适合你。
答案 2 :(得分:0)
从这里的答案输入,我得到了以下解决方案:
(Mis)将Backgroundworker的ReportProgress方法与EventWaitHandle结合使用。如果我想与用户进行交互,我会调用ReportProgress方法并在等待时设置后台进程。在ReportProgress事件的Handler中,我进行了交互,完成后,我发布了EventWaitHandle。
BackgroundWorker bgw;
public MainWindow()
{
InitializeComponent();
bgw = new BackgroundWorker();
bgw.DoWork += new DoWorkEventHandler(bgw_DoWork);
bgw.RunWorkerCompleted += new RunWorkerCompletedEventHandler(bgw_RunWorkerCompleted);
bgw.WorkerReportsProgress = true;
bgw.ProgressChanged += new ProgressChangedEventHandler(bgw_ProgressChanged);
}
// Starting the time consuming operation
private void Button_Click(object sender, RoutedEventArgs e)
{
bgw.RunWorkerAsync();
}
// using the ProgressChanged-Handler to execute the user interaction
void bgw_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
UserStateData usd = e.UserState as UserStateData;
// UserStateData.Message is used to see **who** called the method
if (usd.Message == "X")
{
// do the user interaction here
UserInteraction wnd = new UserInteraction();
wnd.ShowDialog();
// A global variable to carry the information and the EventWaitHandle
Controller.instance.TWS.Message = wnd.TextBox_Message.Text;
Controller.instance.TWS.Background.Set();
}
}
void bgw_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
MessageBox.Show(e.Result.ToString());
}
// our time consuming operation
void bgw_DoWork(object sender, DoWorkEventArgs e)
{
Thread.Sleep(2000);
// need 4 userinteraction: raise the ReportProgress event and Wait
bgw.ReportProgress(0, new UserStateData() { Message = "X", Data = "Test" });
Controller.instance.TWS.Background.WaitOne();
// The WaitHandle was released, the needed information should be written to global variable
string first = Controller.instance.TWS.Message.ToString();
// ... and again
Thread.Sleep(2000);
bgw.ReportProgress(0, new UserStateData() { Message = "X", Data = "Test" });
Controller.instance.TWS.Background.WaitOne();
e.Result = first + Controller.instance.TWS.Message;
}
我希望我没有忽视一些关键问题。我对多线程并不那么熟悉 - 也许在某个地方应该有一些锁(对象)?
答案 3 :(得分:0)
特别针对您的情况
private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e)
{
Thread.Sleep(1000);
var a = Test1("a");
Thread.Sleep(1000);
var b = (string)Invoke(new Func<string>(() => Test2("b")));
MessageBox.Show(a + b);
}
private string Test1(string text)
{
if (this.InvokeRequired)
return (string)this.Invoke(new Func<string>(() => Test1(text)));
else
{
MessageBox.Show(text);
return "test1";
}
}
private string Test2(string text)
{
MessageBox.Show(text);
return "test2";
}
Test2
是一种常规方法,您必须从后台工作者调用。 Test1
可以直接调用,并使用安全模式来调用自身。
MessageBox.Show
类似于yourForm.ShowDialog
(两者都是模态的),您将参数传递给它(text
)并返回值(可以是{{1}的属性值当窗体关闭时设置。我使用的是yourForm
,但它显然可以是任何数据类型。