下面的代码给我发表评论，将其放入数据库，然后等待页面重新加载以显示评论。如何将提交的评论与新评论一起发布后立即显示？这是完成这些工作的代码： 布局：
<table>
<tr>
<td colspan="2">All Comments</td>
<td>
 
</td>
</tr>
<tr> <td colspan="2"> </td></tr>
<tr>
<td>
<asp:Repeater ID="Repeater1" runat="server" ItemType="SiteStiri.Models.Comments" SelectMethod="GetComments" >
<ItemTemplate>
<table>
<tr>
<td colspan="2">
<asp:Label id="lblDate" runat="server" Text='<%# Item.ReleaseDate %>'></asp:Label>
</td>
</tr>
<tr>
<td colspan="3">
<asp:Label ID="lblComment" runat="server" Text='<%# Item.Comment %>'>
</asp:Label>
</td>
</tr>
</table>
</ItemTemplate>
<SeparatorTemplate>
<hr />
</SeparatorTemplate>
<AlternatingItemTemplate>
<table>
<tr>
<td colspan="2">
<asp:Label id="Label1" runat="server" Text='<%# Item.ReleaseDate %>'></asp:Label>
</td>
</tr>
<tr>
<td colspan="3">
<asp:Label ID="Label2" runat="server" Text='<%# Item.Comment %>'>
</asp:Label>
</td>
</tr>
</table>
</AlternatingItemTemplate>
</asp:Repeater>
</td>
</tr>
</table>
</td>
</tr>
<td>
<table>
<tr>
<td colspan="2" >Add Your Comment</td>
</tr>
<tr>
<td colspan="2">
<asp:Label ID="lblStatus" runat="server" Visible="False"></asp:Label>
</td>
<td>
 
</td>
</tr>
<tr>
<td colspan="2">
<asp:TextBox ID="txtcomment" runat="server" TextMode="MultiLine">
</asp:TextBox>
</td>
<td>
 
</td>
</tr>
<tr>
<td>
<asp:Button ID="btnSubmit" runat="server" Text="Submit" OnClick="btnSubmit_Click" />
</td>
<td>
 
</td>
</tr>
</table>
</table>
</td>
</tr>
</table>
代码背后：
public void fnSubmitComment()
{
AddComment cmt = new AddComment();
String x = Request.QueryString["newsID"].ToString();
int y = Convert.ToInt32(x);
bool addSucces = cmt.Addcomment( y , txtcomment.Text);
if (addSucces)
{
lblStatus.Text = "Your Comment has been Added Successfully.";
}
else
{
lblStatus.Text = "Your Comment has not been Added.";
}
}
protected void btnSubmit_Click(object sender, EventArgs e)
{
fnSubmitComment();
}
public IQueryable<Comments> GetComments()
{
var _db = new SiteStiri.Models.CommentsContext();
IQueryable<Comments> query = _db.Comments;
String x = Request.QueryString["newsID"].ToString();
int y = Convert.ToInt32(x);
query = query.Where(p => p.NewsID == y);
return query;
}
我听说我可以用ajax做到这一点？ （我对ajax的了解目前是0）关于我如何做到这一点的任何提示？
答案 0 :(得分：1)
您必须在更新面板中包装转发器， 设置UpdateMode =＆＃34;条件＆＃34;并在btnSubmit上添加一个触发器，以便在单击按钮时更新具有正常页面生命周期的转发器
请记住在代码隐藏中添加commet之后绑定转发器，并且必须在页面中出现ScriptManager控件
或多或少
<asp:ScriptManager runat="server" />
<table>
<tr>
<td colspan="2">All Comments</td>
<td> 
</td>
</tr>
<tr>
<td colspan="2"></td>
</tr>
<tr>
<td>
<asp:UpdatePanel runat="server" UpdateMode="Conditional">
<ContentTemplate>
<asp:Repeater ID="Repeater1" runat="server" ItemType="SiteStiri.Models.Comments" SelectMethod="GetComments">
<ItemTemplate>
<table>
<tr>
<td colspan="2">
<asp:Label ID="lblDate" runat="server" Text='<%# Item.ReleaseDate %>'></asp:Label>
</td>
</tr>
<tr>
<td colspan="3">
<asp:Label ID="lblComment" runat="server" Text='<%# Item.Comment %>'>
</asp:Label>
</td>
</tr>
</table>
</ItemTemplate>
<SeparatorTemplate>
<hr />
</SeparatorTemplate>
<AlternatingItemTemplate>
<table>
<tr>
<td colspan="2">
<asp:Label ID="Label1" runat="server" Text='<%# Item.ReleaseDate %>'></asp:Label>
</td>
</tr>
<tr>
<td colspan="3">
<asp:Label ID="Label2" runat="server" Text='<%# Item.Comment %>'>
</asp:Label>
</td>
</tr>
</table>
</AlternatingItemTemplate>
</asp:Repeater>
</ContentTemplate>
<Triggers>
<asp:AsyncPostBackTrigger ControlID="btnSubmit" />
</Triggers>
</asp:UpdatePanel>
</td>
</tr>
<tr>
<td>
<table>
<tr>
<td colspan="2">Add Your Comment</td>
</tr>
<tr>
<td colspan="2">
<asp:Label ID="lblStatus" runat="server" Visible="False"></asp:Label>
</td>
<td> 
</td>
</tr>
<tr>
<td colspan="2">
<asp:TextBox ID="txtcomment" runat="server" TextMode="MultiLine">
</asp:TextBox>
</td>
<td> 
</td>
</tr>
<tr>
<td>
<asp:Button ID="btnSubmit" runat="server" Text="Submit" OnClick="btnSubmit_Click" />
</td>
<td> 
</td>
</tr>
</table>
</td>
</tr>
</table>