Question

我将大型unicode字符（0x10000 +）存储为long类型，最终需要转换为NSStrings。可以将较小的unicode字符创建为unichar，并使用

创建NSString

[NSString stringWithCharacters:(const unichar *)characters length:(NSUInteger)length]

因此，我认为从unicode long值获取NSString的最佳方法是首先从unichar*值获取long。关于我如何做到这一点的任何想法？

Answer 1

是否有任何理由将值存储为long s？对于Unicode存储，您只需将值存储为UInt32，这样可以通过执行以下操作轻松将数据解释为UTF-32：

int numberOfChars = 3;
UInt32* yourStringBuffer = malloc(sizeof(UInt32) * numberOfChars);
yourStringBuffer[0] = 0x2F8DB; //杞
yourStringBuffer[1] = 0x2318;  //⌘
yourStringBuffer[2] = 0x263A;  //☺

NSData* stringData = [NSData dataWithBytes:yourStringBuffer length:sizeof(UInt32) * numberOfChars];

//set the encoding according to the current byte order
NSStringEncoding encoding;
if(CFByteOrderGetCurrent() == CFByteOrderBigEndian)
    encoding = NSUTF32BigEndianStringEncoding;
else
    encoding = NSUTF32LittleEndianStringEncoding;

NSString* string = [[NSString alloc] initWithData:stringData encoding:encoding];

free(yourStringBuffer);

NSLog(@"%@",string);

//output: 杞⌘☺

在objective-c中将long值转换为unichar *

1 个答案: