Question

我有一个简化的表myowner.mydable，至少列为order_nr，the_days，我是一个多级选择查询

select * from (
    select

sum（..）函数在内部选择查询中不起作用。如何在内部选择中使用函数???

(select sum(the_days) from myowner.mydable where order_nr=confnr) "thedays",--this is a line 4
confnr as order_nr
from (
    select order_nr as confnr,the_days from myowner.mydable WHERE order_nr='5276751'
) as t
union all

然后我得到另一个order_nr

    select
        (select sum(the_days) from myowner.mydable where order_nr=confnr) "thedays",
        confnr as order_nr
    from (
        select order_nr as confnr,the_days from myowner.mydable WHERE order_nr='5276751'
    ) as t

) as t2

选择（.....）作为。但选择（（.....）为t union all（.....）为t），因为t2给出错误：

Could not execute statement.
Feature, scalar value subquery (at line 4) outside of a top level SELECT
list, is not supported. 
-- (opt_Select.cxx 2238)
SQLCODE=-1001030, ODBC 3 State="HY000"
Line 1, column 1

如何摆脱错误？

Answer 1

如果您经常需要执行此查询，可以尝试根据此查询创建视图并使用它。

此外，您的子查询看起来很奇怪。这样：

select
    (select sum(the_days) from myowner.mydable where order_nr=confnr) "thedays",
    confnr as order_nr
from (
    select order_nr as confnr,the_days from myowner.mydable WHERE order_nr='5276751'
) as t

等于：

select sum(the_days), order_nr from myowner.mydable where order_nr = '5276751'
group by order_nr

UPD 完整查询您可以这样转换：

select t.category, t.def_or_indef, t.book_date, t.book_code, t.revenue, 
       t2.conf_nr,
       t2.mydays,
       t.revenue / t2.mydays
  from (select  category, def_or_indef, book_date, book_code,
        revenue, 
        confnr as conf_nr
      from (select CASE WHEN status = 'status1' OR status = 'status2' THEN 'category1' ELSE 'category2' END AS category,
              CASE WHEN status = 'status1' OR status = 'status2' THEN 'definite' ELSE 'indefinite' END AS def_or_indef,
              book_date, 
              book_code, 
              revenue, 
              conf_nr as confnr
          from myowner.mydable 
        WHERE days > 0 
          AND book_date IS NOT NULL 
          AND DATE(dateadd(year,-1,dateadd(day,-day(today()),today()))) < book_date 
          AND book_date <=  date(dateadd(day,-day(today()),today()))) as t
        union all
        select ..  from ( select .. WHERE ..  AND DATE(dateadd(day,-day(today()),today())) < resv_date and resv_date < today() 
         ) as t,
  (select conf_nr, sum(days) as mydays
    from myowner.mydable 
   group by conf_nr) t2

Answer 2

我提出了一个真实的问题：

select * from (
    select
        category, def_or_indef, book_date, book_code,
        (select sum(days) from myowner.mydable where conf_nr=confnr) as mydays,
        revenue, confnr as conf_nr,
        revenue / (select sum(days) from myowner.mydable where conf_nr=confnr) as adr
    from (
        select
            CASE WHEN status = 'status1' OR status = 'status2' THEN 'category1' ELSE 'category2' END AS category,
            CASE WHEN status = 'status1' OR status = 'status2' THEN 'definite' ELSE 'indefinite' END AS def_or_indef,
            book_date, book_code, revenue, conf_nr as confnr
        from myowner.mydable 
        WHERE days > 0 AND book_date IS NOT NULL AND
            DATE(dateadd(year,-1,dateadd(day,-day(today()),today()))) < book_date AND book_date <=  date(dateadd(day,-day(today()),today()))
    ) as t
    union all
    select ..  from ( select .. WHERE ..  AND
        DATE(dateadd(day,-day(today()),today())) < resv_date and resv_date < today()
    ) as t
) as t2

你能给予同等的工作吗？

Oracle IQ数据库中的多级选择和功能

2 个答案: