如何从unix中的平面文件中解析奇数字段？

Question

我有一个平面文件，我想从所有行中解析奇数列。

我是UNIX的新手，我接触的方式就是这个

awk 'BEGIN{ FS = OFS = "|" } { for (i=2;i<=NF;i++) { if(i%2==0) { print $i }}}' newProcessFile.txt

显然它没有产生所需的输出。 我究竟做错了什么 ？请解释 。

Answer 1

您可以执行此操作awk

awk '{for (i=1;i<=NF;i+=2) printf "%s ",$i;print ""}' file

它会打印每隔一列。

cat file
one
one two
one two three
one two three four
one two three four five
one two three four five six

awk '{for (i=1;i<=NF;i+=2) printf "%s ",$i;print ""}' file
one
one
one three
one three
one three five
one three five

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使用其他分隔符：

cat file
one
one|two
one|two|three
one|two|three|four
one|two|three|four|five
one|two|three|four|five|six

awk -F\| '{s="";for (i=1;i<=NF;i+=2) {s=s?s FS $i:$i} print s}' file
one
one
one|three
one|three
one|three|five
one|three|five