将2个sql表行合并为一个

Question

我正在尝试将以下行合并到一个记录中。我希望将[贷款人员]和[房地产经纪人]的名字显示在一行上。任何帮助将不胜感激。

这是我现在的位置

SELECT DISTINCT z.State
       ,z.County
       ,z.City
       ,cr.ZipCode
       ,cr.Route
       ,UPPER(c1.LastName) + ', ' + UPPER(c1.FirstName) AS 'Loan Officer'
       ,UPPER(c2.LastName) + ', ' + UPPER(c2.FirstName) AS 'Realtor'
       ,cr.ID
FROM Prospecting.ZipCodeCarrierRoute  cr WITH (NOLOCK)
       INNER JOIN ZIPCodes z WITH (NOLOCK)
              ON z.ZipCode = cr.ZipCode
       LEFT JOIN Prospecting.Contact_CarrierCode_Assignments cca WITH (NOLOCK)
              ON cca.ZipCodeCarrierRouteID = cr.ID
       LEFT JOIN Prospecting.Contact c1 WITH (NOLOCK)
              ON c1.ContactID = cca.ContactID
                     AND c1.ContactTypeID = 1
       LEFT JOIN Prospecting.Contact c2 WITH (NOLOCK)
              ON c2.ContactID = cca.ContactID
                     AND c2.ContactTypeID = 2
WHERE cr.ID = 875

这是结果

这就是我要找的东西

Answer 1

您可以使用group by：

轻松完成此操作

SELECT z.State, z.County, z.City, cr.ZipCode, cr.Route,
       MAX(UPPER(c1.LastName) + ', ' + UPPER(c1.FirstName)) AS [Loan Officer],
       MAX(UPPER(c2.LastName) + ', ' + UPPER(c2.FirstName)) AS [Realtor],
       cr.ID
FROM Prospecting.ZipCodeCarrierRoute  cr WITH (NOLOCK)
       INNER JOIN ZIPCodes z WITH (NOLOCK)
              ON z.ZipCode = cr.ZipCode
       LEFT JOIN Prospecting.Contact_CarrierCode_Assignments cca WITH (NOLOCK)
              ON cca.ZipCodeCarrierRouteID = cr.ID
       LEFT JOIN Prospecting.Contact c1 WITH (NOLOCK)
              ON c1.ContactID = cca.ContactID
                     AND c1.ContactTypeID = 1
       LEFT JOIN Prospecting.Contact c2 WITH (NOLOCK)
              ON c2.ContactID = cca.ContactID
                     AND c2.ContactTypeID = 2
WHERE cr.ID = 875
GROUP z.State, z.County, z.City, cr.ZipCode, cr.Route, cr.ID