Question

我的应用程序中有一个子片段，我试图测试功能。想法是textview将更新以模仿输入edittext的内容。但是目前它并不喜欢setText，我不知道为什么。我已经检查过我是否错过了导入，我认为小部件是正确定义的。关于如何解决这个问题的任何建议都会很棒。

import com.actionbarsherlock.app.SherlockFragment;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.EditText;
import android.widget.TextView;

public class WeightFragment extends SherlockFragment {

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    View rootView = inflater.inflate(R.layout.fragment_weight, container, false);
    return rootView;
}

EditText weight = (EditText) getActivity().findViewById(R.id.weightInput);
TextView label = (TextView) getActivity().findViewById(R.id.weightResult);

String result = weight.getText().toString();
label.setText(result);

}

Answer 1

将代码INSIDE放在一个方法中，如下所示：

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    View rootView = inflater.inflate(R.layout.fragment_weight, container, false);

    EditText weight = (EditText) getActivity().findViewById(R.id.weightInput);
    TextView label = (TextView) getActivity().findViewById(R.id.weightResult);

    String result = weight.getText().toString();
    label.setText(result);
    return rootView;
}

无法解析符号＆＃34; setText＆＃34; SherlockActionBar片段

1 个答案: