Question

我正在尝试遍历json对象并将选定的值推送到数组中。

$json = '
{
    "canonicalUrl": "/v1/products(offers.type=deal_of_the_day)?format=json&apiKey=946n9vuhdkgeyz2qx2dpxd54",
    "currentPage": 1,
    "from": 1,
    "partial": false,
    "products": [
        {
            "active": true,
            "activeUpdateDate": "2014-11-03T19:43:46",
            "lowPriceGuarantee": true,
            "name": "LG - 1.1 Cu. Ft. Mid-Size Microwave - Black",
            "new": false,
            "onSale": true,
            "productId": 1219180376135,
            "regularPrice": 124.99,
            "salePrice": 99.99,
            "sku": 5998225,
            "source": "bestbuy",
            "startDate": "2014-07-06",
            "type": "HardGood"
        },
        {
            "active": true,
            "activeUpdateDate": "2014-11-03T18:03:02",
            "lowPriceGuarantee": false,
            "name": "Rocketfish In-Wall HDMI Cable",
            "new": false,
            "onSale": true,
            "productId": 1218343205770,
            "regularPrice": 29.99,
            "salePrice": 24.99,
            "sku": 2634897,
            "source": "bestbuy",
            "startDate": "2011-08-14",
            "type": "HardGood"
        }
    ],
    "queryTime": "0.004",
    "to": 2,
    "total": 2,
    "totalPages": 1,
    "totalTime": "0.020"
}

';

$json_output = json_decode($json);
$pBB = array("title" => array(), "type" => array());
foreach($json_output->products as $obj){
    array_push($pBB['title']," {$obj->name}");
    array_push($pBB['type']," {$obj->type}" );

}
echo  json_encode($pBB);

上述代码的输出是

{
  "title": [
    " LG - 1.1 Cu. Ft. Mid-Size Microwave - Black",
    " Rocketfish In-Wall HDMI Cable"
  ],
  "type": [
    " HardGood",
    " HardGood"
  ]
}

我想按以下方式返回

[
  {
     "title": "LG - 1.1 Cu. Ft. Mid-Size Microwave - Black",
     "type": "HardGood"
  },
  {
     "title": " Rocketfish In-Wall HDMI Cable",
     "type":  " HardGood"
  }
]

有什么想法吗？

Answer 1

根据my comment on your question，您使用了一种非常规的方法将产品组织为值，您应该将每个产品组织成包含其标题和类型的每个产品的单独数组。请改用：

$json_output = json_decode($json);
$pBB = array();
foreach($json_output->products as $obj){
    $pBB[] = array(
        'title' => " {$obj->name}", // Not sure why you're using " {$obj->name}" but I preserved it
        'type' => " {$obj->type}", // You could just use $obj->type directly
    );
}
echo  json_encode(array_values($pBB));

Answer 2

$json_output = json_decode($json);
$pBB = array();
foreach($json_output->products as $obj){
    array_push($pBB, array(
        'title' => " {$obj->name}",
        'type' => " {$obj->type}"
    ));
}
echo  json_encode(array_values($pBB));

Answer 3

试试这个！你需要创建对象并推入数组。

$json = ' { "from": 1, "to": 2, "total": 2, "currentPage": 1, "totalPages": 1, "queryTime": "0.004", "totalTime": "0.020", "partial": false, "canonicalUrl": "/v1/products(offers.type=deal_of_the_day)?format=json&apiKey=946n9vuhdkgeyz2qx2dpxd54","products": [ { "sku": 5998225, "productId": 1219180376135, "name": "LG - 1.1 Cu. Ft. Mid-Size Microwave - Black", "source": "bestbuy", "type": "HardGood", "startDate": "2014-07-06","new": false, "active": true, "lowPriceGuarantee": true, "activeUpdateDate": "2014-11-03T19:43:46", "regularPrice": 124.99, "salePrice": 99.99, "onSale": true},{ "sku": 2634897, "productId": 1218343205770, "name": "Rocketfish In-Wall HDMI Cable", "source": "bestbuy", "type": "HardGood", "startDate": "2011-08-14", "new": false, "active": true,"lowPriceGuarantee": false, "activeUpdateDate": "2014-11-03T18:03:02", "regularPrice": 29.99, "salePrice": 24.99, "onSale": true } ] }';

$json_output = json_decode($json);
foreach($json_output->products as $obj){
    $new_obj = new stdClass();
    $new_obj->title = $obj->name;
    $new_obj->type = $obj->type;    
    $pBB[]= $new_obj;
}
echo  json_encode($pBB);

Answer 4

构建JSON对象时出错。实际上你在json_decode函数中传递的字符串是可以的，但是当你从数组构建一个JSON对象时会出现问题。

不要使用

$ pBB = array（＆＃34; title＆＃34; =＆gt; array（），＆＃34; type＆＃34; =＆gt; array（））;

而不是尝试

$ pBB = array（array（＆＃34; title＆＃34; =＆gt; $ title，＆＃34; type＆＃34; =＆gt; $ type））;

当您将$ pBB编码为Json时，我猜它会为您提供准确的输出。

快乐编码。阿图尔

Answer 5

echo  json_encode($pBB);

你需要确保它似乎可以成为JS的数组（即顺序编号）

用

替换上面的行

echo  json_encode(array_values($pBB));

使其按预期工作

数组值返回顺序整数作为键

如何操作数组使其在PHP中作为json结构返回？

5 个答案: