Question

我在oracle 11g中使用XmlType，我有一个这样的标签：

**<ProprietaryId Namespace="CMA_ID">ad017f3a9736ce9d8cbbfc89955aa033 </ProprietaryId>**

我想知道如何获取＆＃34; NameSpace＆＃34;的信息。？

以下是我正在使用的代码：

SELECT extractvalue( value (sr),'*/ReleaseId/ProprietaryId' )as ProprietaryId
  FROM XML_TABLE X,
       table(xmlsequence (extract(dados, '*/ContainedReleaseList/Release' )))sr

但我只能获取标签的信息而不是名称空间。

Answer 1

您需要使用@来指定您需要其值的属性。

这是一个示例查询。

SQL> with x(y) as (
select '<?xml version="1.0" encoding="UTF-8"?>
<service_orders count="1">
      <ProprietaryId Namespace="CMA_ID">ad017f3a9736ce9d8cbbfc89955aa033 </ProprietaryId>
</service_orders>' from dual
)
select
    extractvalue(xmltype(y),'service_orders/ProprietaryId/@Namespace')  as ProprietaryNamespace
from
    x;

PROPRIETARYNAMESPACE
-----------------------
CMA_ID

但EXTRACTVALUE已被弃用。您可以使用XMLTABLE。

SQL> with x(y) as (
select '<?xml version="1.0" encoding="UTF-8"?>
<service_orders count="1">
      <ProprietaryId Namespace="CMA_ID">ad017f3a9736ce9d8cbbfc89955aa033 </ProprietaryId>
</service_orders>' from dual
)
select
    prop.ProprietaryNamespace
from
    x,
    xmltable('service_orders/ProprietaryId'
        passing xmltype(x.y)
        columns ProprietaryNamespace varchar2(20) path '@Namespace'
        ) prop;

PROPRIETARYNAMESPACE
--------------------
CMA_ID

如何在xmltype标记中获取名称空间值？

1 个答案: