C strcmp将字符串与数组的前x个字符进行比较

Question

我想比较两个字符串，但我要找的字是40个字符的数组。所以我想要的是比较单词，与数组的前40个字符。

我该怎么做？

所以：

words[1] = "apple"
words2[1] = a
words2[2] = p
words2[3] = p
words2[4] = l 
words2[5] = e

代码

int j;
for(j = 0; j < i; j++)
{
    printf("%s\n", words[j]);

    if (strcmp (words[j], words2[]) == 0)
    {
    // found it
    }
}

Answer 1

strstr将获取两个以空字符结尾的字符串，并告诉您是否在另一个字符串中。此示例在word

中查找array

#include<stdio.h>
#include<stdlib.h>

int main() {
    char array[] = {"an array of several words"};
    char word[] = { " of "};
    char *pchar = NULL;

    pchar = strstr ( array, word);
    if ( pchar) {
        printf ( "found %s in %s\n", word, array);
    }

    return 0;
}