Question

我正在尝试使用powershell加载xml并显示没有设置父级的节点的所有名称。这可能吗？

到目前为止，这是我的代码：

[xml]$changesXML = Get-Content $PathToXML
function ReplaceOneFormat
{
    Param(
        $Parent
    )
    foreach($child in $Parent)
    {
        $child.Name?
        #ReplaceOneFormat $child # call this function by recursive
    }
}

ReplaceOneFormat $changesXML

所以，这是我的例子xml：

<?xml version="1.0"?>
<books>
  <book author="a">1</book>
  <book author="b">2</book>
  <book author="c">
    <page>796</page>
    <language>USA</language>
    <Publisher>USAFM</Publisher>
  </book>
  <journal>L2</journal>
  <journal>
    <book author="d">L3</book>
    <Publisher>USAFM</Publisher>
  </journal>
</books>

我需要这样的结果：

    Node:       Value:  
    books       
    book        1
    book        2
    book        
    page        796
    language    USA
    Publisher   USAFM
    journal     L2
    journal 
    book        L3
    Publisher   USAFM

Answer 1

我创建示例，循环所有节点。希望这对你有帮助！

[xml]$changesXML = Get-Content $NameFile
$tmp = $changesXML.SelectNodes("//*")
$cnt = $tmp.Count

for ($i = 0; $i -lt $tmp.Count; $i++) {
 "Attributes:"+$tmp.Item($i).Attributes
 "BaseURI:"+$tmp.Item($i).BaseURI
 "ChildNodes:"+$tmp.Item($i).ChildNodes
 "InnerText:"+$tmp.Item($i).InnerText
 "Name:"+$tmp.Item($i).Name
 "LocalName:"+$tmp.Item($i).LocalName
 "NamespaceURI:"+$tmp.Item($i).NamespaceURI
 "NodeType:"+$tmp.Item($i).NodeType
 "Prefix:"+$tmp.Item($i).Prefix
 "**********************************************"
}

通过powershell获取xml中的所有子项，而不使用命名标记

1 个答案: