Question

我最近开始使用python编程。在我的研究和学习中，我所做的其中一个课程是Code Academy上的简单计数游戏。我对它很感兴趣，并希望扩展它的功能并同时将其用作学习工具。

到目前为止，我已经从中学到了很多东西，但是我此刻已经遇到了一个问题，如果他们想要再次播放，我会尝试让用户提示。我认为最好的方法是将游戏嵌套在循环中，如果他们拒绝，则exit()。

然而，我遇到的问题是，即使他们再次进入"y"进行游戏，游戏仍然会退出。我已经考虑过递归地调用main()，但我已经知道这是一个糟糕的编程习惯，因为它只是叠加你使用它越多。即使是测试它，它也不起作用。

from random import randint

def main():
    random_number = randint(1, 10)
    play = "y"
    while "y" in play:
        guesses_left = 3
        while guesses_left > 0:

            try:
                guess = int(raw_input("Guess your number(1 to 10): "))

            except ValueError:
                print "Enter a valid number"
                continue

            if guess == random_number:
                print "You win!"
                play = raw_input("Would you like to play again (y/n): ")
                if "n" or "N" in play:
                    exit()
                else:
                    break

            if guess not in range(1, 10):
                print "Please enter a number between 1 and 10"
                continue

            guesses_left -= 1
            if guesses_left > 0:

                if guess > random_number:
                    print "That was wrong. Guess a lower number"
                    continue

                if guess < random_number:
                    print "That was wrong. Guess a higher number"
                    continue

                if guesses_left == 0:
                    print "You lose! The correct number was %s" % random_number
                    play_again = raw_input("Would you like to play again?(y/n):")

                    if "n" or "N" in play:
                         exit()
                else:
                    break

main()

Python while循环嵌套问题

0 个答案: