Question

所以我编写了一个超级简单的计数器来返回字母比例：

def hasnoe(word):
    count = 0
    for letter in word:
        if letter == 'e':
            count += 1.0
    ratio = count / (len(word))
    return ratio

hasnoe('eeeeeeheif')

但是当我试用它时，计算机没有返回任何值 - 这是什么？

Answer 1

您不能从函数返回多次。您目前在循环的第一个字母后返回count，因此它只能是0或1。

要解决此问题，您只需删除return count

即可

def hasnoe(word):
    count = 0
    for letter in word:
        if letter == 'e':
            count += 1.0
    ratio = count/(len(word))
    return ratio

>>> hasnoe('eeeeeeheif')
0.7

Answer 2

>>> from collections import Counter
>>> s = 'eeeeeeheif'
>>> c = Counter(s)
>>> c
Counter({'e': 7, 'i': 1, 'h': 1, 'f': 1})
>>> den = float(len(s))
>>> freq = dict((k, v/den) for k, v in c.iteritems())
>>> freq
{'i': 0.1, 'h': 0.1, 'e': 0.7, 'f': 0.1}

Answer 3

尝试使用此代码返回两次

 def hasnoe(word):
        count = 0
        for letter in word:
            if letter == 'e':
                count += 1.0
        ratio = count/(len(word))
        return ratio

    hasnoe('eeeeeeheif')

Answer 4

如果你想要两个号码，你最好的选择是返回一个元组。

def hasnoe(word):
    count = 0
    for letter in word:
        if letter == 'e':
            count += 1.0
    ratio = count/(len(word))
    return ratio, count

ratio, count = hasnoe('eeeeeeheif')

创建简单的字母计数器

4 个答案: