我尝试this教程使用ajax和php从我的mysql数据库发送/检索数据。 这是ajax部分:
<script>
function showUser(str) {
if (str=="") {
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function() {
if (xmlhttp.readyState==4 && xmlhttp.status==200) {
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","suchen_ma.php?id="+str,true);
xmlhttp.send();
}
</script>
.php文件如下所示:
<?php
//Connection Details
$username = 'root';
$password = '';
$hostname = 'localhost';
$databasename = 'plzdb';
$id = ($_GET['id']);
//Connection-string
$con = mysqli_connect($hostname,$username,$password,$databasename);
//SQL Query
$sql = "SELECT per_vorname,per_nachname from plz_person
WHERE per_id = $id";
$result = mysqli_query($con,$sql);
echo "<table border='0'>
<tr>
<th></th>
<th></th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['per_vorname'] . "</td>";
echo "<td>" . $row['per_nachname'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
数据在php文件中格式化,但我想发送&#34; raw&#34;数据返回到html并将其显示在列表中并使用css格式化。不幸的是我不知道该怎么做
答案 0 :(得分:0)
只需将数据作为JSON:
返回$sql = "SELECT per_vorname,per_nachname from plz_person
WHERE per_id = " . mysqli_real_escape_string($con, $id);
$result = mysqli_query($con, $sql);
while ($row = mysqli_fetch_array($result)) {
$persons[] = array(
"vorname" => $row['per_vorname'],
"per_nachname" => $row['per_nachname']
);
}
echo json_encode($persons);
然后在javascript中创建一个循环来构建HTML。
注意:通过转义字符串来避免sql注入。