perl脚本将输入转换为JSON

时间:2014-11-06 10:00:48

标签: json perl

抱歉,我是JSON的新手,想写一个Perl脚本,可以将少量输入转换成JSON(格式如下)。要读取的值是" name"," location"," job"是这样的..还有一些子资源类型需要定义,应按以下方式构建..

输入或读取这些属性和值的最佳方法是什么?那是一个简单的文本文件还是每个属性的excel(名称,位置等)?有什么建议吗?

[{
"name":"James Anderson"
"location":"States"
"qualifier":{ 
    "job":"auto dealer"
    "experience":"20"
            },
          "Children": [
            {
                "name":"Mark Brown"
                "age":"15"
            }
                      "education": {
                          "college":"University of Texas"
                                   }      
            {
                "name":"Steve Brown" 
                "age":"10"
            }
                      ]
}
{
"name":"Mark Jones"
"location":"London"
"qualifier":{ 
    "country":"UK"
    "job":"business"
    "citizen":"no"
             }
}
]

0 个答案:

没有答案