Question

在bash脚本中，我需要用一些heredoc替换文件中的占位符字符串。我该怎么做？

e.g。 sed -i 's/PLACEHOLDER_TEXT/$HEREDOC/g' > file.txt其中

<<HEREDOC
Some multiple
lines of
text to replace PLACEHOLDER_TEXT
HEREDOC

Answer 1

通过临时文件并避免替换，因为可能发生替换模式特殊字符的行为（如&，\x）

所以

cat > /tmp/HereFile <<HEREDOC
Some multiple
lines of
text to replace PLACEHOLDER_TEXT
HEREDOC

sed '/PLACEHOLDER_TEXT/ {
   r /tmp/HereFile
   d
   }' YourFile
rm /tmp/HereFile

Answer 2

将其展平（您可以更改＃，如果数据可能出现在您的数据中），然后将新行重新放入其中：

sed "s/PLACEHOLDER_TEXT/$(echo "$HEREDOC"|tr "\n" "#")/g;s/#/\n/g" file.txt

构建$ HEREDOC变量：

$> export HEREDOC=$(cat<<EOF

    > what is going 
    > on with 
    > this 
    > thing
    > EOF
    > )

Answer 3

尝试此命令：

val=$(tr '\n' ' ' < PlaceHolderText.txt); sed "s/PLACEHOLDER/$val/" File.txt

示例：

sdlcb@Goofy-Gen:~/AMD$ cat PlaceHolderText.txt
Some multiple
lines of
text to replace

sdlcb@Goofy-Gen:~/AMD$ cat File.txt
This is a text with PLACEHOLDER for some additional data.

sdlcb@Goofy-Gen:~/AMD$ val=$(tr '\n' ' ' < PlaceHolderText.txt); echo $val; sed "s/PLACEHOLDER/$val/" File.txt
This is a text with Some multiple lines of text to replace  for some additional data.

在bash中使用sed用heredoc替换字符串

3 个答案: