Java平均值和高于平均值

Question

我制作了一个程序，您必须找到用户输入的10个整数的平均值，然后让程序告诉我用户输入的数量实际上高于平均值，然后实际打印出来数字。我有问题告诉我什么是高于平均水平和他们是谁。相反，在计算平均值之后，它只是在输出

中继续给我这样的东西

平均值高于0 这些数字是：0

我做错了什么？

public class Average {
static Scanner keyboard = new Scanner(System.in);
static int sum = 0, aboveAverage;
static double average;

public static void main(String[] args) {
    int[] listOfInt = new int[10];// 10 integers MAX

    System.out.println("Enter " + listOfInt.length + " integers: ");
    for (int count = 0; count < listOfInt.length; count++) {
        listOfInt[count] = keyboard.nextInt();
    }
    for (int count = 0; count < listOfInt.length; count++) {
        sum = sum + listOfInt[count];
    }
    average = sum / listOfInt.length;// sum divided by 10
    System.out.println("Average: " + average);

    if (aboveAverage > average);

    System.out.println("There are " + aboveAverage+ " numbers above the average");
    System.out.println("Those numbers are: " + aboveAverage);
}

}

Answer 1

您的if块以分号结束;你可以像这样修理它

if (aboveAverage > average) { //;
  System.out.println("There are "+aboveAverage+" numbers above the average");
  System.out.println("Those numbers are: " + aboveAverage);
}

修改

在审核其余代码时，我认为您确实需要（使用diamond operator <>）

double average = ((double) sum) / listOfInt.length;// sum divided by 10
System.out.printf("Average: %.2f%n",  average);
List<Integer> aboveAverage = new ArrayList<>();
for (int v : listOfInt) {
    if (v > average) {
        aboveAverage.add(v);
    }
}
System.out.printf("There are %d numbers above the average%n",
        aboveAverage.size());
System.out.printf("Those numbers are: %s%n", aboveAverage);

修改2

全部放在一起，

public static void main(String[] args) {
    Scanner keyboard = new Scanner(System.in);
    int[] listOfInt = new int[10];// 10 integers MAX

    System.out.println("Enter " + listOfInt.length + " integers: ");
    for (int count = 0; count < listOfInt.length; count++) {
        listOfInt[count] = keyboard.nextInt();
    }
    int sum = 0;
    for (int i : listOfInt) {
        sum += i;
    }
    double average = ((double) sum) / listOfInt.length;
    System.out.printf("Average: %.2f%n", average);
    List<Integer> aboveAverage = new ArrayList<>();
    for (int v : listOfInt) {
        if (v > average) {
            aboveAverage.add(v);
        }
    }
    System.out.printf("There are %d numbers above the average%n",
            aboveAverage.size());
    System.out.printf("Those numbers are: %s%n", aboveAverage);
}

Answer 2

  System.out.print("How many numbers will you like to find the Average for:");

  int values;
  values = input.nextInt();
  int counter = values;
  int number;
  int total = 0;

  while (counter > 0) {
       System.out.print("Please enter a number: ");
       number = input.nextInt();
       total = total + number;
       counter = counter - 1;
  }
  average = ((double) total / values)

  System.out.println("The Average is: " + average);