Question

代码中的注释是我试图让它做的，将数组从“12345,12345,12345更改为111,222,333,444,555”

 public void reorganize()
{

     for(int y = 0; y < repeat; y++)//this loop reorganizes the arrays. Each array is now organized by number location rather than how it was inputted. Ex: 12345, 12345, 12345 is now 111,222,333,444,555
   {
        for(int r = 0; y==4; r++)
        {
        newNumbers[r][y] = numbers[y][r];   
        }            
    }

我一直在努力解决这个问题，并且我已经重写了几次，但它永远不会最终正常工作。这是我第一次在SO上发帖，我希望你们能帮助我（：

谢谢

Answer 1

这样的事情：

    Integer[][] numbers = new Integer[5][3];
    // Fill numbers
    Integer[][] newNumbers = new Integer[3][5];

    for(int y = 0; y < numbers.length; y++)//this loop reorganizes the arrays. Each array is now organized by number location rather than how it was inputted. Ex: 12345, 12345, 12345 is now 111,222,333,444,555
    {
        for(int r = 0; r < numbers[0].length; r++)
        {
            newNumbers[r][y] = numbers[y][r];
        }
    }

Answer 2

我建议您首先传递numbers数组并返回newNumbers数组。基本上，您的逻辑应该旋转输入numbers数组的维度以构造newNumbers，但是您的复制逻辑是正确的（一旦您修复了循环测试条件）。

public static int[][] reorganize(int[][] numbers) {
    int[][] newNumbers = new int[numbers[0].length][numbers.length];
    for (int y = 0; y < numbers.length; y++) {
        for (int r = 0; r < numbers[y].length; r++) {
            newNumbers[r][y] = numbers[y][r];
        }
    }
    return newNumbers;
}

然后你应该能够像

那样进行测试

public static void main(String[] args) {
    int[][] numbers = { { 1, 2, 3, 4, 5 }, { 1, 2, 3, 4, 5 },
            { 1, 2, 3, 4, 5 } };
    int[][] newNumbers = reorganize(numbers);
    System.out.println(Arrays.deepToString(newNumbers));
}

输出（按要求）

[[1, 1, 1], [2, 2, 2], [3, 3, 3], [4, 4, 4], [5, 5, 5]]

在Java中重新组织2d数组

2 个答案: