Question

以下是asp成员资格提供者的表。我正在尝试添加同一应用程序的多个用户，但我无法在ApplicationId列中添加重复值。为什么会这样？

这是我用于在表中插入记录的查询：

Insert into Users 
values ('97C84F32-26A6-4A6C-960E-89A6A14D54E4', 'C2CADEDE-DA70-4C25-B717-6970344C8B34', 'John_doe', '', '', 1, '2014-11-05 21:28:33.043')

Insert into Users 
values ('97C84F32-26A6-4A6C-960E-89A6A14D54E4', 'D2CADEDE-CA70-4C25-B717-6970344C8B34', 'John_doe1', '', '', 1, '2014-11-05 21:28:33.043')

错误

无法在对象＆＃39; dbo.Users＆＃39;中插入重复的键行。具有唯一索引＆＃asp ;_Users_Index＆＃39;。重复键值为（97c84f32-26a6-4a6c-960e-89a6a14d54e4，）。

这是我的用户表查询：

CREATE TABLE [dbo].[Users]
(
    [ApplicationId] [uniqueidentifier] NOT NULL,
    [UserId] [uniqueidentifier] NOT NULL,
    [UserName] [nvarchar](256) NOT NULL,
    [LoweredUserName] [nvarchar](256) NOT NULL,
    [MobileAlias] [nvarchar](16) NULL,
    [IsAnonymous] [bit] NOT NULL,
    [LastActivityDate] [datetime] NOT NULL,

    PRIMARY KEY NONCLUSTERED ([UserId] ASC)
        WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, 
              ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO

ALTER TABLE [dbo].[Users] ADD  DEFAULT (newid()) FOR [UserId]
GO

ALTER TABLE [dbo].[Users] ADD  DEFAULT (NULL) FOR [MobileAlias]
GO

ALTER TABLE [dbo].[Users] ADD  DEFAULT ((0)) FOR [IsAnonymous]
GO

ALTER TABLE [dbo].[Users] WITH CHECK 
    ADD FOREIGN KEY([ApplicationId])
    REFERENCES [dbo].[Applications] ([ApplicationId])
GO

任何帮助都会非常感激

Answer 1

您收到的错误是因为PRIMARY KEY列上的表格中有UserId。这意味着您无法在该列中插入具有相同值的多个行。

如果要插入相同的UserId但ApplicationId不同，则应将主键更改为包含UserId和ApplicationId的复合键。< / p>

或者，可能是您的INSERT语句需要更改，因为您依赖于列位置正确。而是指定列：

Insert into Users
(ApplicationId, UserId, UserName, LoweredUserName, MobileAlias, IsAnonymous, LastActivityDate)
values
('97C84F32-26A6-4A6C-960E-89A6A14D54E4','C2CADEDE-DA70-4C25-B717-6970344C8B34','John_doe','','',1,'2014-11-05 21:28:33.043')

Insert into Users
(ApplicationId, UserId, UserName, LoweredUserName, MobileAlias, IsAnonymous, LastActivityDate)
values
('97C84F32-26A6-4A6C-960E-89A6A14D54E4','D2CADEDE-CA70-4C25-B717-6970344C8B34','John_doe1','','',1,'2014-11-05 21:28:33.043')

<强>更新

通过一些研究，默认情况下aspnet_Users表在UserId和LoweredUserName上有一个独特的索引。只需指定一个唯一的LoweredUserName值：

Insert into Users
(ApplicationId, UserId, UserName, LoweredUserName, MobileAlias, IsAnonymous, LastActivityDate)
values
('97C84F32-26A6-4A6C-960E-89A6A14D54E4','C2CADEDE-DA70-4C25-B717-6970344C8B34','John_doe','john doe','',1,'2014-11-05 21:28:33.043')

Insert into Users
(ApplicationId, UserId, UserName, LoweredUserName, MobileAlias, IsAnonymous, LastActivityDate)
values
('97C84F32-26A6-4A6C-960E-89A6A14D54E4','D2CADEDE-CA70-4C25-B717-6970344C8B34','John_doe1','john_doe1','',1,'2014-11-05 21:28:33.043')

唯一标识符Sql

1 个答案: