Question

我试图在Illustrator中为pathItems内的compoundPathItem着色。我的对象看起来像圆圈内的圆圈。 compoundPathItems内没有笔画，四条路径，两条compoundPathItem。

当我使用此行调试时：alert（doc.compoundPathItems [0]）I get:-[CompoundPathItem] .... which makes sense because I've combined two compoundPathItems.

但是，我似乎无法访问pathItems以便为它们着色：

doc.compoundPathItems[0].compoundPathItems[0].pathItems ... errors out x_x ... 
alert(doc.compoundPathItems[0].pathItems.length) gives me 0 .... T-T

请帮助我了解这里发生的事情。

Answer 1

如果所有pageItems都是compoundItems，app.activeDocument.pathItems将在文档中提供所有pathItems，则此脚本将有效。它还将嵌套在compoundPathItem中。所以试试它是否适合你

var currentDocument = app.activeDocument;
var pathItems = currentDocument.pathItems;
var redSwatch = currentDocument.swatches.getByName('CMYK Red');
var blueSwatch = currentDocument.swatches.getByName('CMYK Blue');
for (var i = 0; i < pathItems.length; i++) {
    pathItems[i].filled = true;
    pathItems[i].fillColor = redSwatch.color;
    pathItems[i].stroked = true;
    pathItems[i].strokeColor = blueSwatch.color;
}

Answer 2

是对象的形状，如字母“O”？或“◎”＆gt;复合路径项中的两个compoundPathItem

我认为最后为compound_path_item着色的所有path_item都填充了颜色父对象（= compound_path_item）。

如果字母“O”，请尝试以下代码

#target "Illustrator"
var doc = app.documents[0];
var co_pathitem = doc.compoundPathItems[0].pathItems;

// create colors
var color1 = new RGBColor();
color1.red = 255;

var color2 = new RGBColor();
color2.blue = 255;

// fillcolor red
co_pathitem[0].filled = true;
co_pathitem[0].fillColor = color1;
$.writeln(co_pathitem[0].fillColor.properties()); // => color1

// fillcolor blue
co_pathitem[1].filled = true;
co_pathitem[1].fillColor = color2;
$.writeln(co_pathitem[1].fillColor.properties()); // => color2

// => doc.compoundPathItems[0] will be colored with color2(colored at last)

// but pathItems[0] filled with color1 yet
$.writeln(co_pathitem[0].fillColor.properties()); // => color1

Object.prototype.properties = function (cr) {
  var self = this;
  var cr = cr || ", ";
  var props = [];
  for (var i in self) {
    try {
      props.push(i + ":" + self[i]);
    } catch (e) {
      // props.push(i + ":" + e);
    }
  };
  return props.join(cr);
}

Answer 3

重点是：如果要解压缩目标compoundPathItem，则不仅会得到很多pathItem。您将在子组中获得groupItems，另一个compoundPathItems，pathItems等。整个结构与创建compoundPath之前的状态相同。获取所有pathItems的唯一方法是doc.pathItems。但是您可以做到这一点，并检查compoundPathItem.layer（它的父层）和每个pathItem的父层是否在同一层。所以，这对我来说很完美：

var whiteColor = new CMYKColor();
whiteColor.black = 0;

var doc = app.activeDocument;
//....defining targetLayer here
var whitePathItem = targetLayer.compoundPathItems[0]; //Target layer contains our compound Path
var parentLayer = whitePathItem.layer;

for(var i = 0; i < doc.pathItems.length; i++) {
    var pathItem = doc.pathItems[i];
    if(pathItem.layer == parentLayer) pathItem.fillColor = whiteColor;
}

只需检查父层，这就是窍门！

如何着色嵌套复合路径Extendscript for Illustrator CS5？

3 个答案: