Question

我在创建SQL查询时遇到问题。

本申请的目的是使每个月的第一个定义两个值之间的差异。

以下是我构建的查询：

SELECT 
   Date, 
   Compteur - (SELECT MAX(Compteur)
               FROM SnmpDataPages
               WHERE IP = t1.ip AND ( Date < t1.Date) AND Compteur IS NOT NULL) AS diff, 
   IP
FROM 
   SnmpDataPages AS t1
WHERE 
   Compteur IS NOT NULL 
   AND Date BETWEEN dateadd(YEAR, -1, CAST(getdate() AS DATE)) AND CAST(getdate() AS DATE)
ORDER BY 
   Date, diff DESC

返回此输出：

Date        Diff    IP
---------------------------------
2014-11-04  5075    149.0.15.40 
2014-11-04  1623    149.0.19.177
2014-11-04  1264    149.0.19.77
etc.

此请求适用于“每日”差异，但不适用于月度差异..（我每个月搜索差异第一条记录..）并且分组子查询似乎不可能......

表SnmpDataPage每天递增，parc中的每个外围设备的ip和那里的计数器（总页数）

示例：

id      IP          Counter Date        Model
-----------------------------------------------
28780   100.0.15.51 140064  2014-10-08  Lexmark
28781   100.0.15.53 243617  2014-10-08  Lexmark
28782   100.0.15.55 24101   2014-10-08  Samsung
28783   100.0.15.56 135907  2014-10-08  Brother

44000   100.0.15.51 200000  2014-11-08  Lexmark
44001   100.0.15.53 250000  2014-11-08  Lexmark
44002   100.0.15.55 24200   2014-11-08  Samsung
44003   100.0.15.56 230000  2014-11-08  Brother

我需要的输出:(计数器（M-（M-1）））

date         diff      IP
-----------------------------------
2014-11-08   59936     100.0.15.51
2014-11-08   6383      100.0.15.53
etc.

Answer 1

试试这个让我知道。

    CREATE TABLE #tmp
    (
        ID INT,
        IP varchar(50),
        [counter] INT,
        date DATETIME,
        model VARCHAR(500)
    )

    INSERT INTO #tmp     ( ID, IP, counter, date, model ) VALUES  (1,'100.0.10.11',140064,'2014-10-08','Lexmark' )
    INSERT INTO #tmp     ( ID, IP, counter, date, model ) VALUES  (1,'100.0.10.11',200000,'2014-10-08','Lexmark' )


    SELECT * FROM #tmp

    SELECT IP,MONTH(date),MAX([counter])-MIN([counter]),model FROM #tmp
GROUP BY IP,MONTH(date),model

Answer 2

模拟数据

create table #SnmpDataPage (id int, IPaddress varchar(50), TheCounter int, TheDate datetime, Model varchar(50))

insert into #SnmpDataPage values (28780, '100.0.15.51', 140064, '2014-10-08', 'Lexmark')
insert into #SnmpDataPage values (28781, '100.0.15.53', 243617, '2014-10-08', 'Lexmark')
insert into #SnmpDataPage values (28782, '100.0.15.55', 24101, '2014-10-08', 'Samsung')
insert into #SnmpDataPage values (28783, '100.0.15.56', 135907, '2014-10-08', 'Brother')

insert into #SnmpDataPage values (44000, '100.0.15.51', 200000, '2014-11-08', 'Lexmark')
insert into #SnmpDataPage values (44001, '100.0.15.53', 250000, '2014-11-08', 'Lexmark')
insert into #SnmpDataPage values (44002, '100.0.15.55', 24200, '2014-11-08', 'Samsung')
insert into #SnmpDataPage values (44003, '100.0.15.56', 230000, '2014-11-08', 'Brother')

查询上个月做差异

select  #SnmpDataPage.TheDate, #SnmpDataPage.IPaddress, #SnmpDataPage.Model,
        #SnmpDataPage.TheCounter - Allrecords.TheCounter as TheDifference
from #SnmpDataPage
    join (  select TheDate, TheCounter, IPAddress
            from #SnmpDataPage
         ) Allrecords 
            on  #SnmpDataPage.IPaddress = AllRecords.IPaddress 
            and datediff(month, #SnmpDataPage.TheDate, AllRecords.TheDate) = -1

<强>结果

 TheDate       IPaddress     Model   TheDifference
2014-11-08    100.0.15.51   Lexmark      59936
2014-11-08    100.0.15.53   Lexmark      6383
2014-11-08    100.0.15.55   Samsung      99
2014-11-08    100.0.15.56   Brother      94093

这也可以扩展到前几个月。如果我添加以下测试数据，它将在结果中返回8行，显示前4行中10-08和09-08之间的差异：

insert into #SnmpDataPage values (18780, '100.0.15.51', 40064, '2014-09-08', 'Lexmark')
insert into #SnmpDataPage values (18781, '100.0.15.53', 43617, '2014-09-08', 'Lexmark')
insert into #SnmpDataPage values (18782, '100.0.15.55', 4101, '2014-09-08', 'Samsung')
insert into #SnmpDataPage values (18783, '100.0.15.56', 35907, '2014-09-08', 'Brother')

SQL Server差异值每月在2行之间

2 个答案: