Question

如果我想传递ID的列表/字符串，我应该在下面的StoredProc中定义我的数据类型。（1,2,5,12,99）？

create PROCEDURE [dbo].[TABLE_Delete]
    -- Add the parameters for the stored procedure here
    @TId datatype = null
AS
BEGIN 
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

    -- Insert statements for procedure here
    delete from dbo.TABLE T where T.Id in (@TId)

END

我的TId字段属于Int

Answer 1

您需要将数据作为nvarchar(xx)传递，例如＆＃39; 1,2,3,4＆＃39; 然后使用split函数拆分它们并将查询写为

 delete from dbo.TABLE T where T.Id in (dbo.split(@param,','))

以下是分割功能的代码

CREATE FUNCTION Split
(
  @delimited nvarchar(max),
  @delimiter nvarchar(100)
) RETURNS @t TABLE
(
-- Id column can be commented out, not required for sql splitting string
  id int identity(1,1), -- I use this column for numbering splitted parts
  val nvarchar(max)
)
AS
BEGIN
  declare @xml xml
  set @xml = N'<root><r>' + replace(@delimited,@delimiter,'</r><r>') + '</r></root>'

  insert into @t(val)
  select
    r.value('.','varchar(max)') as item
  from @xml.nodes('//root/r') as records(r)

  RETURN
END
GO

Answer 2

分割的另一种方法

CREATE FUNCTION [dbo].[fnSplitString] 
( 
    @string NVARCHAR(MAX), 
    @delimiter CHAR(1) 
) 
RETURNS @output TABLE(splitdata NVARCHAR(MAX) 
) 
BEGIN 
    DECLARE @start INT, @end INT 
    SELECT @start = 1, @end = CHARINDEX(@delimiter, @string) 
    WHILE @start < LEN(@string) + 1 BEGIN 
        IF @end = 0  
            SET @end = LEN(@string) + 1

        INSERT INTO @output (splitdata)  
        VALUES(SUBSTRING(@string, @start, @end - @start)) 
        SET @start = @end + 1 
        SET @end = CHARINDEX(@delimiter, @string, @start)

    END 
    RETURN 
END

Id的列表的存储过程数据类型

2 个答案: