我是python的新手,我需要知道如何分割字符串,以便我可以从分割的字符串中追加所需的标记。
例如,说
a = "ALU02021543 Build ISR52 [10G DPoE]Upstream traffic priority is not accurate and scheduler is mussy in one or different ONUs"
我需要拆分此字符串并附加“ALU02021543 and [10G DPoE]......
”字符串以制表符分隔。我尝试了.split()
函数,但它返回一个字符串,该字符串在0th
索引处包含整个字符串。我不知道该如何处理?
答案 0 :(得分:1)
首先你可以split
你的字符串,然后添加第3个结束的第一个条目:
>>> s=a.split()
>>> s[0]+' '+' '.join(s[3:])
'ALU02021543 [10G DPoE]Upstream traffic priority is not accurate and scheduler is mussy in one or different ONUs'
答案 1 :(得分:0)
更接近OP问题的答案是
a = "ALU02021543\tBuild\tISR52\t[10G DPoE]\tUpstram traffic priority is not accurate and scheduler is mussy in one or different ONUs"
t = a.split("\t")
a_new = " ".join(t[:1]+t[3:])
print a_new
# ALU02021543 [10G DPoE] Upstram traffic priority is not accurate and scheduler is mussy in one or different ONUs
虽然可以用
来写一些更通用的东西strings = do(all,the,required,stuff)
for s in strings:
# do stuff with t_list[0], t_list_[2], etc
t_list = s.split("\t")
...
答案 2 :(得分:0)
尝试通过re.sub
>>> a = "ALU02021543 Build ISR52 [10G DPoE]Upstream traffic priority is not accurate and scheduler is mussy in one or different ONUs"
>>> import re
>>> re.sub(r'\t\w+\t\w+\t', r' ', a)
'ALU02021543 [10G DPoE]Upstream traffic priority is not accurate and scheduler is mussy in one or different ONUs'