我有这段代码:
<?xml version="1.0" encoding="utf-8"?>
<PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android">
<CheckBoxPreference android:key="notification_settings"
android:text="@string/impostazione"
android:id="@+id/save_check"
android:summary="@string/notification_title"
android:defaultValue="false"
></CheckBoxPreference>
</PreferenceScreen>
现在我需要在FragmentA中获取Checkbox值:
sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getActivity());
现在?
答案 0 :(得分:2)
请尝试这种方式,希望这有助于您解决问题。
sharedPreferences.getBoolean("notification_settings",false)
getBoolean():需要两个参数一个是键,另一个是默认值
答案 1 :(得分:0)
sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getActivity());
boolean isChecked = sharedPreferences.getBoolean(getString(R.string.notification_settings), false);
答案 2 :(得分:0)
strings.xml
<string name="notification_setting">notification_settings</string>
---------------------------------
xxx.xml
.....
<CheckBoxPreference android:key="@string/notification_setting"
....
--------------------------------
.java
sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getActivity());
boolean wifiState = sharedPreferences.getBoolean(R.string.setting_wifi_key, false);
wifiState is you value.