Question

我有点麻烦。我试图发送POST并尝试按照文档进行操作，但我似乎无法做到正确。

在github上：https://github.com/trtmn/Python

欢迎拉请求！

# Getting documentation from :
#https://docs.python.org/2/howto/urllib2.html 
import urllib
import urllib2

url = 'https://hooks.slack.com/services/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'
values = {"username": "webhookbot", "text": "This is posted to #general and comes from a bot named webhookbot.", "icon_emoji": ":ghost:"}

data = urllib.urlencode(values)
req = urllib2.Request(url, data)
response = urllib2.urlopen(req)
the_page = response.read()

Answer 1

看起来我需要将其字符串化为JSON（我知道，但不知道如何）。感谢Tim G.的协助。

所以这是功能代码：

import urllib2
import json

url = 'https://hooks.slack.com/services/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'
values = {"username": "webhookbot", "text": "This is posted to #general and comes from a bot named webhookbot.", "icon_emoji": ":ghost:"}

data = json.dumps(values)
req = urllib2.Request(url, data)
response = urllib2.urlopen(req)
the_page = response.read()

Answer 2

使用httplib替代POST：

* import httplib

conn = httplib.HTTPSConnection(host)
conn.request('POST',urI,request_body, headers)    
response = conn.getresponse()
resp_status=response.status
resp_reason=response.reason
resp_body=response.read()
conn.close()*

看看这是否有帮助。

Answer 3

不确定这是否解决了问题，但如果我在网址的末尾添加斜杠，我会在执行代码时收到回复。

url =＆＃39; https://hooks.slack.com/services/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/＆＃39;

通过python发布问题

3 个答案: