可能是一个相对简单的问题,但我找不到答案:
是否可以用一定范围(具有特定半径)的颜色填充圆圈? 或者有2条边框线 - 一条是彩色的,另一条是带有填充色的白色?
style="fill:steelblue; stroke-width: 2px; stroke: #8cc63f;"
我希望在此fiddle中实现类似(或类似)的内容:
答案 0 :(得分:1)
这是你想要的吗? 希望它有所帮助!
var svg = d3.select('body').append('svg')
.attr('class', 'chart')
.attr('width', 300)
.attr('height', 300)
.append('g')
.attr('transform', 'translate(100, 100)');
svg.append('g')
.append('circle')
.attr('r', 30)
.style('stroke', 'red')
.style('stroke-width', '6px')
.style('fill', 'red')
.style('fill-opacity', 0)
;
答案 1 :(得分:1)
从评论中修改:
因为我还没有找到如何应用css" background-image"对于circle
元素,我添加了一种使用js的方法。
或者您可以使用gradients来实现此目的,尤其是radial-gradients
:
var svg = document.querySelectorAll('svg')[0],
r = 30,
cy = 60,
nr = r - (r * 0.7),
c1 = document.querySelectorAll('circle')[0],
//Assuming you already have those ones
//first make a copy of the circle you just made
c2 = c1.cloneNode();
//then apply new styles to the first circle
c1.setAttributeNS(null, "fill", "transparent");
c1.style.stroke = "#8cc63f";
c1.style.strokeWidth = "2px";
c1.parentNode.appendChild(c2);
//and to the new one
c2.setAttributeNS(null, "fill", "red");
c2.style.strokeWidth = "0";
c2.r.baseVal.value = r - nr; //change its radius
//Wrap thoe elements into a single g that will act as one element
var g = document.createElementNS("http://www.w3.org/2000/svg", 'g');
g.appendChild(c2);
g.appendChild(c1);
svg.appendChild(g)

<svg width="720" height="120">
<defs>
<radialGradient id="gradient">
<stop offset="0%" stop-color="red" />
<stop offset="70%" stop-color="red" />
<stop offset="71%" stop-color="transparent" />
</radialGradient>
</defs>
<circle cx="40" cy="60" r="30"></circle>
<circle cx="120" cy="60" r="30" style="fill:url(#gradient); stroke-width: 2px; stroke: #8cc63f;"></circle>
</svg>
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