Question

我试图读取一个文本文件，并且＆＃34;加密＆＃34; /将每个字母从ASCII表转换为+1（我也希望＆＃34;解密＆＃34;所以为-1）。所以＆＃34; a＆＃34;将成为＆＃34; b＆＃34;，＆＃34; b＆＃34;到＆＃34; c＆＃34;等等。我只需要转换字母（忽略其他所有内容，按原样打印）。我对这段代码遇到了麻烦：

        for(int i = 0; i <= words.size(); i++)
        {                
            for(int j = 0; j <= words.get(i).length(); j++)
            {
                char ch = ' ';
                ch = words.get(i).charAt(j);
                ch += 1;                    
                morewords.add(ch);
            }              
            fileOut.print(morewords.get(i)  + " ");
        }

我已经弄明白了如何为char添加+1，但我不确定如何将其添加回数组或正确打印出来（因为＆＃34; morewords.add（ch））＆＃34;只会添加char，而不是转换所有字符添加字符串）。＆＃34; words.get（i）。length（）＆＃34;当我只想要字符串的长度@ position＆＃34; i＆＃34;时，取数组的整个长度＆＃34;单词＆＃34;在数组中，因此它会引发错误，因为数组的长度比字符串字长。我已经被困在这几个小时了，我无法理解。我想也许我不应该把它们作为字符串读出来，应该把它们作为字符读出来，这可能更简单了？

 public static void main(String[] args) {

        Scanner in = new Scanner(System.in);
        ArrayList<String> words = new ArrayList<String>();
        ArrayList<Character> morewords = new ArrayList<Character>();
        String fileName = ""; //Replace Test with this
        File f;
        Scanner fileIn;

        System.out.println("Please enter a file name for encryption: ");
        //fileName = in.nextLine();
        fileName = "Test.txt";


        try
        {
            //Build the file and attach a scanner to it
            f = new File (fileName); 
            fileIn = new Scanner (f);            

            System.out.println(f.exists()); //For errors
            int counting = 0;

            //Reads in indvidual strings. 
            for(counting =0; fileIn.hasNext(); counting++)
            {                
                words.add(fileIn.next());
                System.out.println(words);
            }            

            PrintWriter fileOut = new PrintWriter ("Backwards.txt");

            for(int i = 0; i <= words.size(); i++)
            {                
                for(int j = 0; j <= words.get(i).length(); j++)
                {
                    char ch = ' ';
                    ch = words.get(i).charAt(j);
                    ch += 1;                    
                    morewords.add(ch);
                }              
                fileOut.print(morewords.get(i)  + " ");
            }            

            fileOut.close();            

        }
        catch(FileNotFoundException e)
        {
            System.out.println("Couldn't find file");
        }

    }

Answer 1

for循环中的第一个是正确的

for (int i = 0; i <= words.size()-1; i++){}

如果您从0开始，则以长度为1

结束

我改变的是

PrintWriter fileOut = new PrintWriter("C:/Backwards.txt");
        for (int i = 0; i <= words.size()-1; i++)
        {
            for (int j = 0; j <= words.get(i).length()-1; j++)
            {
                char ch = ' ';
                ch = words.get(i).charAt(j);
                ch ++; // +=1
                morewords.add(ch);
                fileOut.print(ch);
            }
            fileOut.print(" ");
        }

        fileOut.close();

如果我理解正确的话，它输出正确=）

这是我的代码

public static void main(String[] args) throws Exception
{
    BufferedReader inChannel = new BufferedReader(new FileReader("C:/script.txt"));
    BufferedWriter outChannel = new BufferedWriter(new FileWriter("C:/output.txt"));
    String toParse = "";
    while ( (toParse = inChannel.readLine()) != null )
    {
        String toWrite = "";
        for(int i=0; i!=toParse.length();i++)
        {
            char c = toParse.charAt(i);
            if(true) //check if must be encoded or not
            {
                c++;
                toWrite += c;
            }
        }
        outChannel.write(toWrite);
        outChannel.newLine();
    }       
    inChannel.close();
    outChannel.close();
}

希望帮助

加密/解密文件。用于加密/解密的ASCII +1

1 个答案: