我有一个表单,可以帮助用户在登录后登录,用户被定向到他们可以更新其个人资料的仪表板
<form class="form-horizontal" role="form" action="admin_insert_profile.php" enctype="multipart/form-data" method="post">
<h4>Profile Details </h4>
<div class="form-group">
<label class="col-lg-4 control-label">Name</label>
<div class="col-lg-6">
<input class="form-control" value="<?php echo $user_admin_name ;?>" type="text" name="name" >
</div>
</div>
<div class="form-group">
<label class="col-lg-4 control-label">Email</label>
<div class="col-lg-6">
<input class="form-control" value="<?php echo $login_session ;?>" type="email" name="email" >
<p class="help-block"></p>
</div>
</div>
<div class="form-group">
<label class="col-lg-4 control-label">Password</label>
<div class="col-lg-6">
<input class="form-control" value="<?php echo $user_admin_password ;?>" type="password" name="password">
</div>
</div>
<div class="form-group">
<label class="col-md-3 control-label"></label>
<div class="col-md-8">
<input class="btn btn-primary" value="Save Changes" type="submit" name="submit">
<span></span>
</div>
</div>
</form>
admin_insert_profile.php
<?php
$con=mysqli_connect("localhost","root","","db");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// escape variables for security
$name = mysqli_real_escape_string($con, $_POST['name']);
$email = mysqli_real_escape_string($con, $_POST['email']);
$password = mysqli_real_escape_string($con, $_POST['password']);
$sql="UPDATE member SET admin_name = '".$name."', admin_email = '".$email."',admin_password = '".$password."' WHERE id='1' ";
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
header("Location: admin_login.php");
exit;
mysqli_close($con);
?>
成功更新其个人资料后,他们会被注销并重定向到登录页面,在此登录页面上,我希望显示一条消息,说明密码已更新且用户需要再次登录。 有没有办法可以这样做
答案 0 :(得分:4)
是的!.. 您可以将以下代码放在:
admin_insert_profile.php
页面
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
$_SESSION['message']="password has been updated";
header("Location: admin_login.php");
exit;
在login.php
页面中,将代码改为<form>
标记:
<?PHP
if(isset($_SESSION['message'])){
echo $_SESSION['message'];
unset($_SESSION['message']);
}
?>
如果您不使用session_start()
,请在两个页面中使用。
答案 1 :(得分:1)
是的,你可以借助全球变量$_server
和$_session
来做到这一点。如果成功更新集$_SERVER['flag']='set';
,则在登录页面上检查$_SERVER['flag']
变量。
if($_SERVER['flag']=='set')
{
//passwod changed
}
答案 2 :(得分:1)
执行此操作的一种方法是,更新您的admin_insert_profile.php
,如下所示
....
header("Location: admin_login.php?ok=1");
mysqli_close($con); // Move it to here, its never get called
exit;
admin_login.php 中的
这里提供的信息是我用来 如果只是按照 //Check for success flag in get query param
$ok = isset($_GET['ok']);
//Insert this code where you wanted to show the msg
if($ok) {
echo '<div class="alert alert-success" role="alert">
Password has been updated and the user needs to login again
</div>';
}
flash messaging
使用会话function addMsg($msg, $type = 'danger') {
$_SESSION['msg'] = $type .'|'. $msg;
}
function showMsg($class = 'msg') {
$msg = @$_SESSION['msg'];
if(isset($msg) && !empty($msg)) {
$msgPart = explode('|', $msg);
$msgText = ($msgPart[1]);
$msgType = $msgPart[0];
if( !empty($msgText) ) {
//Remove Flash message
unset( $_SESSION['msg'] );
return sprintf('
<div id="flashMsg" class="alert alert-%s">
<button type="button" class="close" data-dismiss="alert" aria-hidden="true">×</button>
%s
</div>
', $msgType, $msgText);
}
}
}
admin_login.php中的//Start the session at top
start_session();
addMsg('Password has been updated and the user needs to login again', 'success');
header("Location: admin_login.php");
mysqli_close($con); // Move it to here, its never get called
exit;
//Start the session at top
start_session();
//put where you wanted to show the flash
echo showMsg();