我希望对数据框进行分组,以包含具有> 1记录的主题的所有记录,并排除那些只有1条记录的主题。
让我们采用以下数据框;
mydata <- data.frame(subject_id = factor(c(1,2,3,4,4,5,5,6,6,7,8,9,9,9,10)),
variable = rnorm(15))
下面的代码为我提供了使用duplicated();
的&gt; 1记录的主题duplicates <- mydata[duplicated(mydata$subject_id),]$subject_id
但我希望保留每个主题所有记录的&gt; 1记录,所以我试过了;
mydata[mydata$subject_id==as.factor(duplicates),]
这不会返回我期待的结果。
有什么想法吗?
答案 0 :(得分:2)
data.table解决方案
set.seed(20)
subject_id <- as.factor(c(1,2,3,4,4,5,5,6,6,7,8,9,9,9,10))
variable <- rnorm(15)
mydata<-as.data.frame(cbind(subject_id, variable))
library(data.table)
setDT(mydata)[, .SD[.N > 1], by = subject_id] # @Thanks David.
# subject_id variable
# 1: 4 -1.3325937
# 2: 4 -0.4465668
# 3: 5 0.5696061
# 4: 5 -2.8897176
# 5: 6 -0.8690183
# 6: 6 -0.4617027
# 7: 9 -0.1503822
# 8: 9 -0.6281268
# 9: 9 1.3232209
答案 1 :(得分:1)
一个简单的替代方法是使用dplyr
:
library(dplyr)
dfr <- data.frame(a=sample(1:2,10,rep=T), b=sample(1:5,10, rep=T))
dfr <- group_by(dfr, b)
dfr
# Source: local data frame [10 x 2]
# Groups: b
#
# a b
# 1 2 4
# 2 2 2
# 3 2 5
# 4 2 1
# 5 1 2
# 6 1 3
# 7 2 1
# 8 2 4
# 9 1 4
# 10 2 4
filter(dfr, n() > 1)
# Source: local data frame [8 x 2]
# Groups: b
#
# a b
# 1 2 4
# 2 2 2
# 3 2 1
# 4 1 2
# 5 2 1
# 6 2 4
# 7 1 4
# 8 2 4
答案 2 :(得分:0)
我必须稍微编辑你的数据框:
set.seed(20)
subject_id <- as.factor(c(1,2,3,4,4,5,5,6,6,7,8,9,9,9,10))
variable <- rnorm(15)
mydata<-as.data.frame(cbind(subject_id, variable))
现在获取出现多次的主题的所有行:
mydata[duplicated(mydata$subject_id)
| duplicated(mydata$subject_id, fromLast = TRUE), ]
# subject_id variable
# 4 4 -1.3325937
# 5 4 -0.4465668
# 6 5 0.5696061
# 7 5 -2.8897176
# 8 6 -0.8690183
# 9 6 -0.4617027
# 12 9 -0.1503822
# 13 9 -0.6281268
# 14 9 1.3232209
编辑:这也可以使用您的duplicates
向量:
mydata[mydata$subject_id %in% duplicates, ]
答案 3 :(得分:0)
Here you go (I changed your variable to var <- rnorm(15):
set.seed(11)
subject_id<-as.factor(c(1,2,3,4,4,5,5,6,6,7,8,9,9,9,10))
var<-rnorm(15)
mydata<-as.data.frame(cbind(subject_id,var))
x1 <- c(names(table(mydata$subject_id)[table(mydata$subject_id) > 1]))
x2 <- which(mydata$subject_id %in% x1)
mydata[x2,]
subject_id var
4 4 0.3951076
5 4 -2.4129058
6 5 -1.3309979
7 5 -1.7354382
8 6 0.4020871
9 6 0.4628287
12 9 -2.1744466
13 9 0.4857337
14 9 1.0245632
答案 4 :(得分:0)
尝试:
> mydata[mydata$subject_id %in% mydata[duplicated(mydata$subject_id),]$subject_id,]
subject_id variable
4 4 -1.3325937
5 4 -0.4465668
6 5 0.5696061
7 5 -2.8897176
8 6 -0.8690183
9 6 -0.4617027
12 9 -0.1503822
13 9 -0.6281268
14 9 1.3232209