Question

我是ASP.NET的新手，我在页面加载时尝试从select设置query中的数据

这是mi表：

区域

ID_Area|ID_Formula|Nombre

现在我的代码

ASPX

<asp:Content runat="server" ContentPlaceHolderID="ContentPlaceHolder1">
<div class="container">
    <div class="row">
        <div class="col-md-6">
            <div class="form-group">
                <label >Nombre de Area</label>
                <asp:TextBox runat="server" ID="area" CssClass="form-control" required="true"></asp:TextBox>
            </div>
            <div class="form-group">
                <label>Formula asociada</label>
                 <select id="Select1" runat="server" name="D1"> </select>
            </div>
            <div class="form-group">
                <asp:Button ID="btn_login" OnClick="docreatearea" CssClass="btn btn-primary btn-lg btn-block" Text="Guardar" runat="server"/>
            </div>

        </div>
    </div>
</div>

ASPX.CS

    protected void Page_Load(object sender, EventArgs e)
{
    if(!IsPostBack){
        string query = @"SELECT * FROM FORMULA";

        using (SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["BancoEstadoConnectionString"].ToString()))
        {
            SqlCommand comand = new SqlCommand(query, conn);

            DataSet ds = new DataSet();
            comand.Fill(ds, "Area");
            conn.Open();
            Select1.DataSource = ds;
            Select1.DataTextField = "Nombre";
            Select1.DataValueField = "Nombre";
            Select1.DataBind();
        }
    }
}

问题出现在fill function，因为SqlCommand object

中存在doenst

我该怎么办呢？修复它？

Answer 1

您的名字中不存在

au_fname 。将其更改为表格中的有效列名称。

Answer 2

Fill命令位于SqlDataAdapter类中。

SqlDataAdapter adapter = new SqlDataAdapter(command);
adapter.Fill(ds);

http://msdn.microsoft.com/en-us/library/system.data.sqlclient.sqldataadapter(v=vs.110).aspx

Answer 3

您需要使用SqlDataAdapter来填充DataSet：

using (SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["BancoEstadoConnectionString"].ToString()))
    {
        SqlCommand comand = new SqlCommand(query, conn);

        DataSet ds = new DataSet();
        conn.Open();

        var adapter = new SqlDataAdapter(command);
        adapter.Fill(ds, "Authors");

        Select1.DataSource = ds;
        Select1.DataTextField = "au_fname";
        Select1.DataValueField = "au_fname";
        Select1.DataBind();
    }

Answer 4

用户下面的页面加载方法代码

if(!IsPostBack){
    string query = @"SELECT * FROM FORMULA";

    using (SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["BancoEstadoConnectionString"].ToString()))
    {
        SqlCommand comand = new SqlCommand(query, conn);
        DataSet ds = new DataSet();
        SqlDataAdapter adp = new SqlDataAdapter(cmd);

        adp.Fill(ds);

        Select1.DataSource = ds;
        Select1.DataTextField = "au_fname";
        Select1.DataValueField = "au_fname";
        Select1.DataBind();
    }
}

如何将数据从数据库传递到ASP.NET中的“选择标记”？

4 个答案: