我是R中循环的新用户,所以希望有人帮助我解决这个问题 我有数据。框架包含20种类型的人口如下
Sample Population R
1 Bari1_062-1 Bari1 94.52303
2 Bari1_062-2 Bari1 98.27683
3 Bari1_062-3 Bari1 100.53170
4 Bari1_062-4 Bari1 96.65940
5 Bari1_062-5 Bari1 117.62474
6 Bari1_063-1 Bari1 144.39547
我需要使用R列来计算每个种群的平均值和方差[我想通过在R中使用循环解决该问题] 感谢
答案 0 :(得分:3)
无需编写循环,这里有一些方法
with(df, tapply(R, Population, function(x) c(mean(x), var(x))))
或者
aggregate(R ~ Population, df, function(x) c(mean(x), var(x)))
或者
do.call(rbind, by(df, df$Population, function(x) c(mean(x$R), var(x$R))))
或者
do.call(rbind, lapply(split(df, df$Population), function(x) c(mean(x$R), var(x$R))))
或者
library(data.table)
setDT(df)[, list(Var = var(R), Mean = mean(R)), by = Population]
或者
library(dplyr)
df %>%
group_by(Population) %>%
summarise(Var = var(R), Mean = mean(R))
如果你坚持要获得for
循环解决方案,那么
预定义结果数据集(因为在循环中增长对象是一种不好的做法)
Res <- data.frame(Population = unique(df$Population),
Mean = rep(NA, length(unique(df$Population))),
Var = rep(NA, length(unique(df$Population))))
运行循环
for(i in unique(df$Population)){
Res$Mean[Res$Population == i] <- mean(df$R[df$Population == i])
Res$Var[Res$Population == i] <- var(df$R[df$Population == i])
}
Res
# Population Mean Var
# 1 Bari1 108.6685 375.0275