Question

我试图从另一个表中的现有变量和选定列插入数据

这是我的代码

$jobtitle=$_POST['jobtitle'];
$jobdescription=$_POST['jobdescription'];
$requirements=$_POST['requirements'];
$resume=$_POST['resume'];
$expyears=$_POST['expyears'];
$submit=$_POST['submit'];
$useremail=$_SESSION['email'];

$insert=mysql_query("INSERT INTO career (jobtitle, jobdescription, requirements, expyears, resume, useremail, resname) VALUES ('$jobtitle','$jobdescription','$requirements','$expyears','$resume','$useremail', SELECT resname FROM restaurant WHERE useremail='$useremail')");

但上面的代码没有给我的数据库带来任何结果

这个问题有什么解决方案吗？

感谢

Answer 1

Note that you shouldn't be using mysql_* functions因为它是一个已弃用的库。考虑转移到mysqli_*或PDO。

话虽如此，您的查询不正确。您无法在VALUES()语句中同时使用INSERT和选择。您应该选择要插入的字符串文字以及您要选择的一个值。

请尝试以下方法：

$query = "
    INSERT INTO career (jobtitle, jobdescription, requirements, expyears, resume, useremail, resname)
    SELECT '$jobtitle','$jobdescription','$requirements','$expyears','$resume','$useremail', resname
    FROM restaurant 
      WHERE useremail='$useremail'
";

从select查询中插入数据

1 个答案: