Libre Office Basic用户定义函数的目标寻求

时间:2014-11-04 15:47:22

标签: libreoffice basic libreoffice-calc libreoffice-basic

我正在尝试使用Libre Office Basic为Libre Office Calc编写用户定义的函数,该函数将Goal Seek作为函数运行,而不是我进入菜单并单击。

我希望能够做的是传递一个单元格作为公式的第一个参数,第二个参数是我想要设置公式的值,第三个参数是包含变量的单元格被操纵。

例如,我想在calc =GSeek2(A1,5,A2)中键入单元格A3,其中A1包含=A2 + 1,A2从0开始,A3等于4。

我认为要操纵的公式和单元格需要通过Goal Seek函数作为地址传递,但我不确定。我尝试了以下代码,但我不断收到“BASIC语法错误。意外的符号:目标。”谁知道我哪里出错?

Function GSeek2(Form As Range, Target as Double, Var as Range)

    Form = Form.Address
    Var = Var.Address

    With Worksheets("Sheet1")
        GSeek2 = .Range(Form).GoalSeek _
        Goal:=.Value(Target).Value, _
       ChangingCell:=.Range(Var)
    End With

End Function

1 个答案:

答案 0 :(得分:0)

Openoffice或libreoffice宏不能像在Excel中一样用VBA编写。所以你的VBA代码不起作用。您必须使用特殊的BASIC方言和openoffice或libreoffice的特殊API。好的起点是https://wiki.openoffice.org/wiki/Documentation/BASIC_Guide

不幸的是,您无法在openoffice或libreoffice中的用户定义函数中将对象作为参数传递。因此,您只能传递单元格地址(工作表,列,行)的单个部分作为参数。

示例:

Function GSeek2(lSheetF as long, lColF as long, lRowF as long, lSheetV as long, lColV as long, lRwoV as long, dTarget as double) as double

 Dim oCellAddressFormula as new com.sun.star.table.CellAddress
 oCellAddressFormula.Sheet = lSheetF-1
 oCellAddressFormula.Column = lColF-1
 oCellAddressFormula.Row = lRowF-1

 Dim oCellAddressVaiable as new com.sun.star.table.CellAddress
 oCellAddressVaiable.Sheet = lSheetV-1
 oCellAddressVaiable.Column = lColV-1
 oCellAddressVaiable.Row = lRowV1-1

 oGoalResult = ThisComponent.seekGoal(oCellAddressFormula, oCellAddressVaiable, dTarget)
 GSeek2 = oGoalResult.Result

End Function

在单元格中使用

=GSEEK2(SHEET(A1),COLUMN(A1),ROW(A1), SHEET(A2),COLUMN(A2),ROW(A2), 5)
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