我有一个用户输入id和密码的登录页面。要重置密码，我必须检查输入的密码是否存在，是否与我输入的id匹配。如何验证它。我无法验证它。如果用户输入任何密码，则显示记录已更新。如何验证它。这是代码
的login.php
<label type="text" name="id" maxlength="50" size="20">ID</label><br />
<input type="text" name="id" placeholder="ID" class="input" size="20"/><br /></div>
<div class="formItem">
<label type="text" name="uid" maxlength="50" size="20">Password</label><br />
<input type="password" name="uid" placeholder="ID" class="input" size="20"/><br /></div>
<span class="field">(* Required field)</span><br /><br />
<input type="submit" name="login1" value="LOGIN" class="button"><br /><br /><br /><br />
</form>
</div>
</body>
</html>
<?php
$username = "root";
$password = "";
$hostname = "localhost";
$db = "abc";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL");
mysql_select_db($db,$dbhandle) or die('cannot select db');
if(isset($_POST['login1']))
{
$id= $_POST['id'];
$uid= $_POST['uid'];
$query= "select * from resume where id='$id'
AND uid='$uid'";
$run= mysql_query($query);
if(mysql_num_rows($run)>0){
echo "<script>window.open('resetp.php','_self')</script>";
}
else {
echo "<script>alert('Login details are incorrect!')</script>";
}
}
?>
resetp.php
<label type="text" name="uid" maxlength="50" size="20">Old Password</label><br />
<input type="text" name="uid" placeholder="id" class="input" size="20"/><br /></div>
<div class="formItem">
<label type="text" name="uid" maxlength="50" size="20">New Password</label><br />
<input type="password" name="pass" placeholder="pass" class="input" size="20"/><br /></div>
<div class="formItem">
<label type="text" name="cpas" maxlength="50" size="20">Confirm Password</label><br />
<input type="password" name="cpas" placeholder="" class="input" size="20"/><br /></div>
<div class="formItem">
<input type="submit" name="login1" value="RESET" class="formButton"><br /><br /><br /><br /></div>
</form>
<?php
$username = "root";
$password = "";
$hostname = "localhost";
$db = "resume1";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL");
mysql_select_db($db,$dbhandle) or die('cannot select db');
if(isset($_POST['login1']))
{
$pass= $_POST['pass'];
$uid= $_POST['uid'];
$cpas=$_POST['cpas'];
$query = "Update `resume` SET uid='".$_POST['pass']."' where uid='".$_POST['uid']."'";
$run = mysql_query($query);
if($query)
{
echo "<script>alert('Record updated')</script>";
}
else
{
echo "<script>alert('no')</script>";
}
}
?>
我如何验证
答案 0 :(得分：1)
Try this:
This line
<label type="text" name="uid" maxlength="50" size="20">New Password</label><br />
should be
<label type="text" name="pass" maxlength="50" size="20">New Password</label><br />
答案 1 :(得分：0)
我想无法理解你的要求。
为什么不像在login.php中那样进行验证
$query= "select * from resume where id='$id'
AND uid='$uid'";
$run= mysql_query($query);.................
答案 2 :(得分：0)
PHP脚本应该在开头，而不是在代码的末尾。从<?php .... ?>开始，然后按照<HTML> ... </HTML>，否则即使在处理脚本之前也会返回结果。
您的代码存在许多安全问题。你可以试试这个。
<?php
require 'db.php';
$username = isset($_POST['username']) ? htmlspecialchars(trim($_POST['username']), ENT_QUOTES, 'UTF-8') : '';
$password = isset($_POST['password']) ? htmlspecialchars($_POST['password'], ENT_QUOTES, 'UTF-8') : '';
$error = array();
$error_found = 0;
if(isset($_POST['submit']) && ($_POST['submit'] == 'Reset'))
{
//check for errors.
//check if username field is empty.
if(empty($username))
{
$error[] = 'Please provide your user-name.';
}
//check if password field is empty.
if(empty($password))
{
$error[] = 'Please provide a password.';
}
//if errors exist, put errors found as true.
if(!empty($error))
{
$error_found = 1;
}
//else no errors are found.
else
{
//proceed to reset.
//connecting to database.
$db = mysql_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASSWORD) or die('Unable to connect, check your connection parameters. ');
mysql_select_db(MYSQL_DB, $db) or die('Could not select database, check availability. ' . mysql_error($db));
//querying the database. Checking if user-name password combination exists.
$query = 'SELECT username FROM resume WHERE username = "' . mysql_real_escape_string($username, $db) .
'" AND password = PASSWORD("' . mysql_real_escape_string($password, $db) . '")';
$result = mysql_query($query, $db) or die(mysql_error($db));
//checking if result is true.
if(mysql_num_rows($result) > 0)
{
//the result is true and so you can now reset your password.
}
else
{
$error[] = 'The username password combination you provided does not exist.';
$error_found = 1;
}
}
}
//HTML
?>
<!DOCTYPE HTML>
<html>
<head><title> ... </title></head>
<body>
<!--Your html code here -->
<?php
//if errors are found, then errors are shown here.
if($error_found == 1)
{
echo '<fieldset><center>';
echo '<ul>';
foreach($error as $e)
{
echo '<li>' . $e . '</li>';
}
echo '</ul>';
echo '</center></fieldset>';
}
?>
<form action="nameOfThisScript.php" method="POST">
Username:<input id="username" type="text" name="username" required />
Password:<input id="password" type="password" name="password" required />
<button id="Reset" type="submit" name="submit" value="Reset">Reset</button>
</form>
</body>
</html>
在与此脚本相同的文件夹中创建名为db.php的脚本，并输入代码
<?php
define('MYSQL_HOST', 'localhost');
define('MYSQL_USER', 'root');
define('MYSQL_PASSWORD', '');
define('MYSQL_DB', 'resume1');
?>
希望这有帮助。