Question

是否可以在Hive中检索上一个星期六的日期。

需要此格式的输出，即“2014-11-01”。

每当运行查询时，它必须返回上一个星期六的日期。

Answer 1

这样做

select  CASE 
WHEN from_unixtime(unix_timestamp(),'EEEE')="Friday" 
THEN Date_add(CAST(from_unixtime(unix_timestamp()-1*60*60*24,'yyyy-MM-dd') as String),-5)
WHEN from_unixtime(unix_timestamp(),'EEEE')="Thursday" 
THEN Date_add(CAST(from_unixtime(unix_timestamp()-1*60*60*24,'yyyy-MM-dd') as String),-4)
WHEN from_unixtime(unix_timestamp(),'EEEE')="Wednesday" 
THEN Date_add(CAST(from_unixtime(unix_timestamp()-1*60*60*24,'yyyy-MM-dd') as String),-3)
WHEN from_unixtime(unix_timestamp(),'EEEE')="Tuesday" 
THEN Date_add(CAST(from_unixtime(unix_timestamp()-1*60*60*24,'yyyy-MM-dd') as String),-2)
WHEN from_unixtime(unix_timestamp(),'EEEE')="Monday" 
THEN Date_add(CAST(from_unixtime(unix_timestamp()-1*60*60*24,'yyyy-MM-dd') as String),-1)
WHEN from_unixtime(unix_timestamp(),'EEEE')="Sunday" 
THEN Date_add(CAST(from_unixtime(unix_timestamp()-1*60*60*24,'yyyy-MM-dd') as String),0)
ELSE Date_add(CAST(from_unixtime(unix_timestamp()-1*60*60*24,'yyyy-MM-dd') as String),-6)
END
from fun;

输出

2014-11-01

Answer 2

Danila Ganchar是对的。这是寻找上周六的最聪明，最快捷的方式。

SELECT date_sub（from_unixtime（unix_timestamp（）），cast（from_unixtime（unix_timestamp（），＆＃39; u＆＃39;）AS int）+ 1）;

Answer 3

以下查询将解决您的问题：

SELECT  date_sub(CURRENT_DATE, cast(from_unixtime(unix_timestamp(), 'u') AS int) + 1);

检索上周六的蜂巢日期

3 个答案: