Question

我正在获取像这样的xml feed

  <?xml version='1.0' encoding='utf-8'?>
  <feed  xmlns="http://www.w3.org/2005/Atoz">
  <entry>
  <title>Php Developer</title>
  <summary type="text">We are required php developer urgently</summary>
  <content type="xhtml">
  <div xmlns="http://www.w3.org/1999/xhtml"><p>Spark Infosys is a professional web development  company in Hyderabad</p>
  <p> Requirements are:</p>
  <p>Job Description:</p>
  <ul>
  <li>Must have excellent exposure on technologies like – Php, MYSQL, Html, Ajax, J Query</li>
  <li>Knowledge of Wordpress, Joomla, Magento , codigniter will be an advantag</li>
  <li>Should be proficient in Designing, Developing and Coding skills</li>
 </ul>
  <p>Requirements:</p>
 <ul>
 <li>Must have Minimum 1 Year experience as PHP Developer</li>
 <li>Willing to work niight shifts also</li>
 </ul>              
 </div>
 </content>
 </entry>
 </feed>

我正在使用rss解析器进行解析。如何使用html标签获取内容标签数据并存储在数据库中。现在我没有得到

 $job_title=mysql_real_escape_string($this->title); 
 $job_summary=mysql_real_escape_string($this->summary);
 $job_content=mysql_real_escape_string($this->content);

在内容部分，当我使用$ this-＆gt; div时，内容数据与html标签一起存储。当我使用$ this-＆gt;内容时，内容数据不会插入数据库中请帮我知道如何使用html标签存储内容数据

如何使用php中的html标记将xml feed内容存储到数据库中

0 个答案: