Notepad ++`在文件中查找'显示除特定关键字之外的所有结果

Question

我使用notepad ++搜索某些关键字（使用正则表达式）。类似的东西（word1 | word2 |这个陈述|另一个陈述）。它有效，但我可以搜索并显示除某个关键字以外的所有结果吗？类似的东西排除下面的单词（排除这个|排除这个）？例如，下面。

samedir \ File1.log

This is line 1
This is line 2
This is line 3
exclude this
This is line 4
This is line 5
This is line 6
not excluded
excluding this

samedir \ File2.log

This is line 1 1
This is line 2 1
This is line 3 1
exclude this
This is line 4 1
This is line 5 1 1
This is line 6 1
not excluded
excluding this

例如：我想在两个文件中启动查找（在同一目录中），但排除包含excluding this和exclude this的行 结果应该显示如下

File1.log

This is line 1
This is line 2
This is line 3
This is line 4
This is line 5
This is line 6
not excluded

File2.log

This is line 1 1
This is line 2 1
This is line 3 1
This is line 4 1
This is line 5 1 1
This is line 6 1
not excluded

Answer 1

你可以用先行断言来做到这一点：

^(?!excluding this|exclude this)[^\r\n]*$

只要它们不包含excluding this或exclude this，就会匹配整行。

关键是(?!)部分。有关详细信息，请参阅http://www.regular-expressions.info/lookaround.html。

Answer 2

您可以尝试使用下面的正则表达式匹配所有不具有exclude或excluding this字符串的行。

^(?!.*\bexclud(?:ing|e) this\b).+$

DEMO

开始时此(?!.*\bexclud(?:ing|e) this\b)否定前瞻声明我们要匹配的行中不存在字符串exclude this或excluding this。也就是说，上述正则表达式将匹配除包含exclude this或excluding this

之外的所有行

Answer 3

我想排除一个字符串并在一行中搜索两个字符串，所以我使用了这个正则表达式： ^(?!.*excludethisstring).*includethisstring1.includethisstring2.$

这将使搜索的一行必须包含两个字符串，如果您想搜索其中任何一行： ^(?!.excludethisstring).(includethisstring1|includethisstring2).*$