如何评估这种参数或者我需要传递JSON?我可以更改参数的结构:"news[0].title"
或“news.0.title"
或其他任何内容,但我不想让我的API用户形成json。
@Autowired
private TemplateEmailBodyPreparer preparer;
public void doIt() {
Map<String,String> properties = new HashMap<String,String>() {{
put("news[0].title", "Title 1");
put("news[0].body", "Body 1");
put("news[1].title", "Title 2");
put("news[1].body", "Body 2");
}};
String result = preparer.getByTemplate("mail/html/news.ftl", properties);
System.out.println("Result = " + result);
}
@Service
public class TemplateEmailBodyPreparer implements EmailBodyPreparer {
@Autowired
private Configuration freeMarkerConfiguration;
public String getByTemplate(String templatePath, Map<String,String> properties) {
try {
Template template = freeMarkerConfiguration.getTemplate(templatePath, "UTF-8");
return FreeMarkerTemplateUtils.processTemplateIntoString(template, properties);
} catch (IOException | TemplateException e) {
throw new IllegalArgumentException("Unable to build template: " + e.getMessage());
}
}
}
邮件/ HTML / news.ftl
<!DOCTYPE html>
<html>
<head></head>
<body>
<#list news as content>
${content.title} - ${content.body}
</#list>
</body>
</html>
错误:
Caused by: java.lang.IllegalArgumentException: Unable to build template: The following has evaluated to null or missing:
==> news [in template "mail/html/news.ftl" at line 5, column 11]
答案 0 :(得分:0)
在您的示例模板中,FreeMarker期望List
的真实news
和真实Map
- s或JavaBeans作为该列表中的项目。它不会解释那些以某种特殊语言编写的关键值(它怎么可能?)。由于您知道密钥的语法,因此您必须将它们解析为List
- s和Map
- s,然后将结果传递给FreeMarker。