Laravel Left加入哪里

时间:2014-11-03 09:49:11

标签: php mysql sql laravel

我的滔滔不绝的模型存在一些问题,我尝试在一个

中加入两个不同的表

现在我有两张表,比如。

第一个表名为“company_saved_cv”

|id|company_id|worker_id |
--------------------------
|1|       2    |  61     |
|3|       3    |  66     |
|4|       2    |  69     |
--------------------------

第二个表名为“workers”

|id|location|name_and_surname|
------------------------------
|61|London  | John John      |
|62|London  | John John      |
|66|London  | John John      |
|67|London  | John John      |
|68|London  | John john      |

我和whana得到这样的表。

|id|location|name_and_surname|worker_id|
---------------------------------------|
|61|London  | John John      |  61     |
|62|London  | John John      | NULL    |
|66|London  | John John      | 66      |
|67|London  | John John      | NULL    |
|68|London  | John john      | NULL    |

我的模型功能在哪里

public static  function CvSearch($interested_field, $location)
{

    $match = "MATCH( `interested_fields`) AGAINST (?)";

    $query = Worker::select('workers.name_and_surname', 'workers.id', 'workers.location','company_saved_cv.worker_id')
        ->leftJoin('company_saved_cv', function($leftJoin)
        {
            $leftJoin->on('company_saved_cv.worker_id', '=', 'workers.id')
                ->where('company_saved_cv.company_id', '=', Session::get('company_id') );


        })
        ->where('workers.location', '=', $location)
        ->whereRaw($match, array($interested_field))
        ->orderBy('workers.created_at')
        ->paginate(10);
    return $query;
}

如果我对此行发表评论:->where('company_saved_cv.company_id', '=', Session::get('company_id') );它正在运行,但我只需要获取employees table中的行,其中company_id = 2(在我的示例中);

Session::get('company_id') = 2 

我将通过在laravel.log文件中记录来检查它。

我认为这是问题所在('company_saved_cv.company_id','=',Session :: get('company_id'));请求,但我无法弄清楚,也许有人可以帮助我?

4 个答案:

答案 0 :(得分:8)

我用这段代码解决了这个问题

 $query = Worker::select('workers.name_and_surname', 'workers.id', 'workers.location','company_saved_cv.worker_id')
        ->leftJoin('company_saved_cv', function($leftJoin)use($company_id)
        {
            $leftJoin->on('workers.id', '=', 'company_saved_cv.worker_id');
            $leftJoin->on(DB::raw('company_saved_cv.company_id'), DB::raw('='),DB::raw("'".$company_id."'"));


        })

答案 1 :(得分:2)

当你使用LEFT JOIN作为INNER JOIN

的地方时

使用LEFT JOIN和WHERE类似

SELECT workers.name_and_surname, workers.id, workers.location,company_saved_cv.worker_id
FROM workers LEFT JOIN company_saved_cv
ON company_saved_cv.worker_id= workers.id
WHERE company_saved_cv.company_id = 2

<强>输出

|id|location|name_and_surname|worker_id|
---------------------------------------|
|61|London  | John John      |  61     |
|66|London  | John John      |  66     |

使用LEFT JOIN和AND

SELECT workers.name_and_surname, workers.id, workers.location,company_saved_cv.worker_id
FROM workers LEFT JOIN company_saved_cv
ON company_saved_cv.worker_id= workers.id
AND company_saved_cv.company_id = 2

<强>输出

|id|location|name_and_surname|worker_id|
---------------------------------------|
|61|London  | John John      |  61     |
|62|London  | John John      | NULL    |
|66|London  | John John      | 66      |
|67|London  | John John      | NULL    |
|68|London  | John john      | NULL    |

新查询

$query = Worker::select('workers.name_and_surname', 'workers.id', 'workers.location','company_saved_cv.worker_id')
        ->leftJoin('company_saved_cv', function($leftJoin)
        {
            $leftJoin->on('company_saved_cv.worker_id', '=', 'workers.id')

                ->on('company_saved_cv.company_id', '=', Session::get('company_id') );


        })

答案 2 :(得分:2)

或多或少是这样的:

$directoryTypeId = 1;

Node::query()
    ->leftJoin('directories', 'directories.id', '=', 'nodes.directory_id')
    ->leftJoin('directory_types', function ($leftJoin) use ($directoryTypeId) {
        $leftJoin
            ->on('directory_types.id', '=', DB::raw($directoryTypeId))
            ->on('directory_types.COLUMN_1', '=', 'directories.COLUMN_2');
    })
    ->select([
        'nodes.id as node_id',
        'directories.name',
        'directory_types.id as type_id',
    ]);

答案 3 :(得分:0)

您可以轻松地使用模型。最后一个表,您可以删除该位置,因为您可以从模型中获取它。轻松创建多对多关系或您想要的东西。查看文档:{​​{3}}