我用随机数在c#中制作了一个二维数组,但我希望这些数字不会重复 例如,给出输入4(x),4(y),15(maxElem)的成功输出将是:
14 | 8 | 1 | 7
3 | 13 | 2 | 4
2 | 6 | 12 | 8
10 | 9 | 4 |
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace TwoDimensionArray
{
class Program
{
static void Main(string[] args)
{
int x = 4;
int y = 4;
int[,] z = new int[x, y];
Random r = new Random();
for (int i = 0; i < x; i++)
{
for (int j = 0; j < y; j++)
{
z[i, j] = r.Next(1, 15);
}
}
for (int i = 0; i < x; i++)
{
for (int j = 0; j < y; j++)
{
if (i == 3 && j == 3)
{
Console.Write(" ");
break;
}
else
{
if (z[i, j] > 9)
Console.Write(z[i, j] + " ");
else
Console.Write(z[i, j] + " ");
}
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
答案 0 :(得分:1)
生成一个包含有效数字的数组,然后use a shuffle algorithm随机化数组中的顺序,最后通过检索来自混洗数组的值来填充二维数组。
答案 1 :(得分:0)
尝试这样做:
int x = 4;
int y = 4;
int[,] z = new int[x, y];
Random r = new Random();
var values =
Enumerable
.Range(1, x * y)
.OrderBy(n => r.Next())
.ToArray();
for (int i = 0; i < x; i++)
{
for (int j = 0; j < y; j++)
{
z[i, j] = values[i * 4 + j];
}
}