Question

我正在使用一个表格，其中信息以JSON格式存储在表格中。 JSON值字段如下所示：

从k2_extra_fields中选择*，其中id = 2且已发布= 1;

id | value        
2,[{"name":"Apples","value":1,"target":null,"alias":"","required":0,"showNull":1},{"name":"Pears","value":2,"target":null,"alias":"","required":0,"showNull":1},{"name":"Mangos","value":3,"target":null,"alias":"","required":0,"showNull":1},{"name":"Guava","value":4,"target":null,"alias":"Fruit","required":0,"showNull":1},{"name":"Pineapple","value":5,"target":null,"alias":"Fruit","required":0,"showNull":1}]

或逐行逐行查看值（减去ID）：

[
  {"name":"Apples","value":1,"target":null,"alias":"","required":0,"showNull":1},
  {"name":"Pears","value":2,"target":null,"alias":"","required":0,"showNull":1},
  {"name":"Mangos","value":3,"target":null,"alias":"","required":0,"showNull":1},
  {"name":"Guava","value":4,"target":null,"alias":"Fruit","required":0,"showNull":1},
  {"name":"Pineapple","value":5,"target":null,"alias":"Fruit","required":0,"showNull":1}
]

引导我的查询返回值3. 3 = Mangos。如何获取'3'值并将其与存储的名称/值匹配，以便我最终得到输出，Mangos？

Answer 1

应该可以使用内置的mysql功能，但非常难，并且不聪明＆＃39;想法。如果你真的需要在mysql中计算这个问题，你需要为你的mysql添加新的功能。查看UDF插件：http://dev.mysql.com/doc/refman/5.1/en/udf-compiling.html

MySQL查询返回json名称值

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