Question

我已经完成了使用C ++编写代码的任务，用户必须猜测1-100之间的数字，然后计算机有20个问题可以尝试猜测这个数字。这是我写的代码：

#include <iostream>
#include <math.h>

using namespace std;

int main()
{
int imax; 
char ans;
int imin;
int i;
const char y = 'y';
const char n = 'n';



imax = 100;
imin = 0;
i = 0;
int e = (imax - imin) / 2;

cout << "Think of a number between 1-100." << endl; 

do
{
    cout << "Is the number equal or greater too " << e << endl;
    cin >> ans;
    if (ans == y)
    {
        cout << "Is the number " << e << endl;
        cin >> ans;
        if (ans == y)
        {
            i = e;
            return i;
        }
        else
        {
            imin = e;

        }           
    }
    else
    {
        imax = e;
    }

} while (i == 0);



cout << "Your number is "<< i << endl;

system("PAUSE");

return 0;
}

代码一直运行，直到它到达第二个if语句。它会接受一个＆＃39; y＆＃39;并询问该号码是否为e，但是如果＆＃39; n＆＃39;得到回答它不会改变imin太e。如果＆＃39; n＆＃39;回答第一个if语句，它不会将imax设置为等于e。我已经在这方面苦苦挣扎了很长一段时间，非常感谢给予的任何帮助。

Answer 1

您没有更改循环中e的值，这就是else条件下无效的原因。你的逻辑也有些错误。试试这个，希望这会有所帮助：

#include <iostream>
#include <math.h>

using namespace std;

int main()
{
int imax; 
char ans;
int imin;
int i;
const char y = 'y';
const char n = 'n';



imax = 100;
imin = 0;
i = 0;

cout << "Think of a number between 1-100." << endl; 

do
{
    int e = imin + ((imax - imin) / 2);
    cout << "Is the number equal or greater too " << e << endl;
    cin >> ans;
    if (ans == y)
    {
        cout << "Is the number " << e << endl;
        cin >> ans;
        if (ans == y)
        {
            i = e;
            break;
        }
        else
        {
            imin = e;

        }           
    }
    else
    {
        imax = e;
    }

} while (i == 0);



cout << "Your number is "<< i << endl;

system("PAUSE");

return 0;
}

Answer 2

EE 273是一场噩梦。我在其他地方找到了这段代码：

#include<iostream>
using namespace std;

const int MAX_VALUE = 100;
const int MIN_VALUE = 1;

int guess;
int high = MAX_VALUE;
int low = MIN_VALUE;

char choice;

int main(){


cout<<"Think about a number between "<<MIN_VALUE<<" and "<<MAX_VALUE<<". \n\n";
guess = ( high-low ) / 2;

while((high-low)!=1){
cout<<"Is your number less than or equal to "<<guess<<"? \nEnter y or n. \n\n";
cin>>choice;

if(choice=='y' || choice=='Y') {
    high = guess;
    guess -= ( high - low ) / 2;
}
else if(choice=='n' || choice=='N') {
    low = guess;
    guess += (high - low ) /2;
}
else cout<<"Incorrect choice."<<endl;


}
cout<<"Your number is: "<<high<<".\n";

system("pause");
return 0;
}

20个问题游戏

2 个答案: